我将向我的 Android 应用程序添加 Spring 的 RESTful Web 服务支持,如此处所述https://spring.io/guides/gs/sumption-rest-android/。
这是顶级 build.gradle 配置:
// Top-level build file where you can add configuration options common to all sub-projects/modules.
buildscript {
repositories {
jcenter()
}
dependencies {
classpath 'com.android.tools.build:gradle:2.1.0'
}
}
allprojects {
repositories {
jcenter()
}
}
这是我的app/build.gradle
配置:
apply plugin: 'com.android.application'
android {
compileSdkVersion 23
buildToolsVersion "23.0.3"
defaultConfig {
applicationId "com.example"
minSdkVersion 8
targetSdkVersion 17
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.txt'
}
}
dependencies {
compile 'com.android.support:appcompat-v7:+'
compile fileTree(dir: 'libs', include: ['*.jar'])
compile 'org.springframework.android:spring-android-rest-template:1.0.1.RELEASE'
compile 'com.fasterxml.jackson.core:jackson-databind:2.3.2'
}
packagingOptions {
exclude 'META-INF/NOTICE' // will not include NOTICE file
exclude 'META-INF/LICENSE' // will not include LICENSE file
}
}
现在它失败并出现以下错误:
FAILURE: Build failed with an exception.
* What went wrong:
Execution failed for task ':app:transformResourcesWithMergeJavaResForDebug'.
> com.android.build.api.transform.TransformException: com.android.builder.packaging.DuplicateFileException: Duplicate files copied in APK META-INF/license.txt
File1: user\.gradle\caches\modules-2\files-2.1\org.springframework.android\spring-android-rest-template\1.0.1.RELEASE\e132d929bd181941f79b0d63edafb8a86ae6fd33\spring-android-rest-template-1.0.1.RELEASE.jar
File2: user\.gradle\caches\modules-2\files-2.1\org.springframework.android\spring-android-core\1.0.1.RELEASE\e68f0e8e4b636ee30c4de58953be38d9b72a5e3b\spring-android-core-1.0.1.RELEASE.jar
我做错了什么以及如何解决?