9

我对命令批处理脚本中的 IF ELSE 有疑问...

在记事本中:
代码:

:CHECKACCOUNT
if /I "%user%"=="insertusername" ( GOTO :ACCOUNT ) ELSE ( GOTO :CHECKPASSACCT )

:CHECKPASSACCT
if /I "%pass%"=="insertpassword" ( GOTO :ACCOUNT ) ELSE ( GOTO :COUNTER )

在命令中:
代码:

(此时出乎意料。

完整的脚本代码:

@echo off

::SETTINGS:::::::::::::::::::::::
set filetxt =userpass.txt
set log=logfile.log
set timer=900
::set default = true
::set user = 0
::set pass = 0
:::::::::::::::::::::::::::::::::


:STARTER
ECHO.>>%log%
ECHO ========START========>>%log%
SetLocal EnableDelayedExpansion
Set n=
Set _InputFile=%filetxt%
For /F "tokens=*" %%I IN (%_InputFile%) DO (
Set /a n+=1
Set acct!n!=%%I
)
set router_ip=%acct1%
set user=%acct2%
set pass=%acct3%
GOTO :CHECKFILE1


:CHECKFILE1
CLS
IF EXIST curl.exe ( GOTO :CHECKFILE2 ) else (
ECHO ERROR: curl.exe was not found.>>%log%
ECHO ERROR: curl.exe was not found.
ECHO.
ECHO.
GOTO :PAUSEEXIT
)

:CHECKFILE2
CLS
IF EXIST sleep.exe ( GOTO :CHECKACCOUNT ) else (
ECHO ERROR: sleep.exe was not found.>>%log%
ECHO ERROR: sleep.exe was not found.
ECHO.
ECHO.
GOTO :PAUSEEXIT
)

:CHECKACCOUNT
if /I "%user%"=="insertusername" GOTO ACCOUNT
GOTO CHECKPASSACCT

:CHECKPASSACCT
if /I "%pass%"=="insertpassword" GOTO ACCOUNT
GOTO COUNTER

:ACCOUNT
CLS
::if %default% = true ( GOTO :COUNTER ) ELSE (
ECHO To edit/change USERNAME and PASSWORD... Please type: OPTION
ECHO.
SET /P user="Please enter the username of your Router:"
IF /I %user%==OPTION ( Goto :EDITBAT )
CLS
ECHO To edit/change USERNAME and PASSWORD... Please type: OPTION
ECHO.
SET /P pass="Please enter the password of your Router:"
IF /I %pass%==OPTION ( Goto :EDITBAT )
CLS
set /a i = 1
GOTO :CHECKACCOUNT
::)

:EDITBAT
start /WAIT notepad %filetxt%
set router_ip=%acct1%
set user=%acct2%
set pass=%acct3%
GOTO :CHECKACCOUNT

:COUNTER
IF %i%==0 ( GOTO :RESETROUTER ) ELSE (
ECHO WAIT %i% seconds...
sleep 1
set /a i = i - 1
CLS
GOTO :COUNTER
)


:RESETROUTER
CLS
ECHO READY to RESET....
ECHO Preparing....
sleep 2

sleep 2
CLS
ECHO Processing....
sleep 5

sleep 2
CLS
ECHO Success....
sleep 5
set /a i = %timer%
CLS
GOTO :COUNTER

:PAUSEEXIT
PAUSE

:EXIT
ECHO.>>%log%
ECHO ========END OF LOG FILE========>>%log%
4

4 回答 4

18

您看到的错误来自错误的格式。不要全部放在 1 行。而是使用这个:

if /I "%user%"=="insertusername" (
     GOTO :ACCOUNT 
) ELSE (
     GOTO :CHECKPASSACCT 
)

更深层次的根本原因是:goto :somewhere命令需要由换行符终止。

于 2010-09-23T13:06:55.070 回答
11

您可以将其简化为:

:CHECKACCOUNT
if /I "%user%"=="insertusername" GOTO ACCOUNT
GOTO CHECKPASSACCT

:CHECKPASSACCT
if /I "%pass%"=="insertpassword" GOTO ACCOUNT
GOTO COUNTER

ELSE不需要这些语句。由于该IF块将跳转到其他地方,因此将第二个GOTO放在下一行或ELSE块中应该是等效的。

此外,在定义目标时需要前导冒号,GOTO但在GOTO语句本身内引用目标名称时不需要。

于 2010-09-20T19:30:45.503 回答
3

该问题与显示的代码无关!

问题在

:COUNTER
IF %i%==0 ( GOTO :RESETROUTER ) ELSE (

由于i未定义变量,该行将扩展为

IF ==0 ( GOTO :RESETROUTER ) ELSE (

那是一个无效的表达。

要发现这种简单的语法失败,您应该使用ECHO ON.

于 2016-04-26T20:46:25.457 回答
0

您不需要使用括号。您基本上是在告诉系统“如果 %user% 是 insertusername (”并且它在问“'(' 应该做什么?”

于 2016-04-26T20:14:33.913 回答