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我正在将JSONEditor集成到 Django 管理员中。我的模型中有一个字段使用 Postgres JSON，并且这个库中的树编辑器非常完美。

模型.py

class Executable(models.Model):
    """ Simplified model for sake of the question."""

    recipe = JSONField(null=True, blank=True)

我已经取得了不错的进展（我认为）将 JSONEditor 库集成到 Django Admin 中适当的创建/编辑屏幕中。加载时数据显示正确，但由于某种原因，当我在 JSONEditorWidget 中进行编辑时，未保存更改。我确定有一些save我需要处理的覆盖，或者我遗漏了一些明显的东西，但我真的不确定从这里去哪里。

管理员.py

import json
from django import forms, utils
from django.contrib import admin

from .models import Executable


class JSONEditorWidget(forms.Widget):
    html_template = """
        <div id='%(name)s_editor_holder'></div>
        <script type="text/javascript">
                var options = {
                    "mode": "tree",
                    "search": true
                };
                var %(name)s_editor = new JSONEditor(container, options);
                var json = %(value)s
                %(name)s_editor.set(json);
                %(name)s_editor.expandAll();

                var json = %(name)s_editor.get(json);
        </script>
        <textarea readonly class="vLargeTextField" cols="40" id="id_%(name)s" name="%(name)s" rows="2" height="20px">%(value)s</textarea>
    """
    def __init__(self, attrs=None, formats=None, defaults=None):
        self.formats = formats
        self.defaults = defaults
        super(JSONEditorWidget, self).__init__(attrs)

    def render(self, name, value, attrs=None):
        if isinstance(value, basestring):  # Edit existing instance
            value = json.loads(value)
        result = self.html_template % {
            'name': name,
            'value': json.dumps(value)
        }
        return utils.safestring.mark_safe(result)


class ExecutableForm(forms.ModelForm):
    recipe = forms.CharField(widget=JSONEditorWidget())    # Kwargs here?

    class Meta:
        model = Executable
        fields = '__all__'

    class Media:
        css = {
            'all': ('http://www.jsoneditoronline.org/app.min.css',)  # TEMP
        }
        js = (
            'http://www.jsoneditoronline.org/app.min.js',   # TEMP
            )


class ExecutableAdmin(admin.ModelAdmin):
    model = Executable
    form = ExecutableForm
    fields = (('request', 'status'), 'recipe')


admin.site.register(Executable, ExecutableAdmin)
4

1 回答 1

13

我对 Django 1.10.2、jsoneditor#^5.5.9、Postgres 9.5 的解决方案：

模型.py

from django.contrib.postgres.fields import JSONField

class Consumer(models.Model):
    data = JSONField(default=dict, db_index=True)

管理员.py：

from django import forms
from django.contrib import admin
from django.utils.safestring import mark_safe
from django.template.loader import render_to_string

from .models import Consumer


class JSONEditorWidget(forms.Widget):

    template_name = 'jsoneditor.html'

    def render(self, name, value, attrs=None):
        context = {
            'data': value,
            'name': name
        }

        return mark_safe(render_to_string(self.template_name, context))


class ConsumerForm(forms.ModelForm):

    class Meta:
        model = Consumer
        fields = '__all__'
        widgets = {
            'data': JSONEditorWidget()
        }

    class Media:
        css = { 'all': ('jsoneditor/dist/jsoneditor.min.css',) }
        js = ('jsoneditor/dist/jsoneditor.min.js', )


class ConsumerAdmin(admin.ModelAdmin):
    list_display = ['pk']
    model = Consumer
    form = ConsumerForm

admin.site.register(Consumer, ConsumerAdmin)

jsoneditor.html：

<div id="{{ name }}_editor"></div>

<textarea cols="40" id="id_{{ name }}" name="{{ name }}" rows="10" required="" style="display: none">{{ data }}</textarea>


<script>
    console.log('jsoneditor.html');
    var container = document.getElementById("{{ name }}_editor");

    var options = {
        modes: ['code', 'tree'],
        search: true,

        onChange: function () {
            var json = editor.get();
            document.getElementById("id_{{ name }}").value=JSON.stringify(json);
        }
    };

    var editor = new JSONEditor(container, options);
    var json = {{ data|safe }};
    editor.set(json);
</script>

用StackEdit编写的块引用。

于 2016-10-30T05:18:21.693 回答