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我不知道如何让我的递归调用在 Scratch 中工作。任何人都可以提出任何建议吗?
change result by (result * number1)增加. result_ result * number1您想result直接设置为result * number1,因此请改用set ... to ...块。
change result by (result * number1)
result
result * number1
set ... to ...