如何使用 bugzilla rest api 报告错误?以下文档指出错误对象或其某些字段必须包含在 POST 正文中。我尝试将字段添加为 POST 方法参数,但我收到此错误“没有为创建提供数据”,状态代码为 400。我的问题是如何在 POST 方法主体中包含错误对象或其某些字段?
https://wiki.mozilla.org/Bugzilla:REST_API:Methods#Create_new_bug_.28.2Fbug_POST.29
String serverURL = "https://api-dev.bugzilla.mozilla.org/test/latest";
String product = "FoodReplicator";
HttpClient client = new HttpClient();
PostMethod method = new PostMethod(serverURL + "/bug?username=abc@xyz.com&password=123456);
method.addParameter("product", "FoodReplicator");
method.addParameter("component", "Salt");
method.addParameter("summary", "testing");
method.addParameter("version", "1.0");
client.executeMethod(method);
return method.getStatusCode() + " " + method.getResponseBodyAsString();