1

我需要一个正则表达式来让用户只有关键字 52 和有关键字 52,53 但没有 54 的用户。下面是表结构

CREATE TABLE `User` (
  `id` int NOT NULL AUTO_INCREMENT,
  `first_name` varchar(100) NOT NULL,
  `last_name` varchar(100) NOT NULL,
  `keywords` text,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

Sample record1:  100, Sam, Thompson, "50,51,52,53,54"
Sample record2:  100, Wan, Thompson, "50,52,53"
Sample record3:  100, Kan, Thompson, "53,52,50,54"

50 = sports
51 = cricket
52 = soccer
53 = baseball
54 = tennis

到目前为止，这是我提出的问题。它提供了所有 3 个记录。

SELECT * FROM `User` WHERE keywords REGEXP '[[:<:]]52,53,54[[:>:]]'
4

2 回答 2

3

尝试使用FIND_IN_SET()而不是复杂的正则表达式：

SELECT u.*
FROM User
WHERE text = '52' OR
    (FIND_IN_SET('52', text) > 0 AND FIND_IN_SET('53', text) > 0 AND
     FIND_IN_SET('54', text) = 0)

解释：

WHERE text = '52' -- users who have keyword 52 and only this keyword
WHERE FIND_IN_SET('52', text) > 0 AND FIND_IN_SET('53', text) > 0 AND
     FIND_IN_SET('54', text) = 0
                  -- users who have keywords 52 and 53 but not 54
于 2016-05-25T04:58:32.033 回答
1 
SELECT * FROM `User` WHERE keywords RLIKE "^52$"; --only 52
SELECT * FROM `User` WHERE keywords RLIKE "(.*(52|53)){2}" AND keywords not RLIKE "54"; -- users who have keywords 52 and 53 but not 54

编辑：记录在案：第二个查询确实应该是not rlike [[:<:]]54[[:>:]]，就像 OP 的原始想法一样，以防止匹配，例如 154。

http://sqlfiddle.com/#!9/cdc530/13

于 2016-05-25T05:08:59.057 回答