2

如果我从这里复制代码:https
://jsfiddle.net/agt10exp/ 它在小提琴上工作正常,但是当我在我的电脑上创建一个新文件并将代码粘贴到其中时,我得到相同的布局,但是它是无法正常运行(将<html></html>and添加<script src....></script>到我的代码中:
(Ps 我是 Python 程序员,所以问题可能出在我的 HTML/Js 知识上)

<html>
I am a </span><select name="parent_selection" id="parent_selection">
            <option value="">-- Please Select --</option>
            <option value="patient">Patient</option>
            <option value="doctor">Doctor or physician</option>
            <option value="school">School or parent</option>
            <option value="worker">Case worker</option>
        </select>
        <br /><span>and I need information on</span>
        <select name="child_selection" id="child_selection" onchange="location = this.options[this.selectedIndex].value;">
        </select>
</html>


<!------answer 1: not wokring --------------->
<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>

var jq81 = jQuery.noConflict();
jq81(document).ready(function($){
//let's create arrays
var patient = [
    {display: "My initial visit", value: "patients#visit" },
    {display: "My initial evaluation", value: "patients#visit" },
    {display: "My appointments", value: "patients#appointments" },
    {display: "Your payment policies", value: "patients#policies" }];

var doctor = [
    {display: "Our approach", value: "doctors-and-physicians" },
    {display: "Our services", value: "services" },
    {display: "Referring patients", value: "patients#visit" }];

var school = [
    {display: "Our approach", value: "schools-and-parents" },
    {display: "My child's initial evaluation", value: "patients#visit" },
    {display: "Setting appointments", value: "patients#appointments" },
    {display: "Your payment policies", value: "patients#policies" }];

var worker = [
    {display: "Our approach", value: "case-workers" },
    {display: "Insurance policies", value: "clients#insurance" },
    {display: "Your Payment policies", value: "patients#policies" }];

//If parent option is changed
jq81("#parent_selection").change(function() {
        var parent = jq81(this).val(); //get option value from parent

        switch(parent){ //using switch compare selected option and populate child
              case 'patient':
                list(patient);
                break;
              case 'doctor':
                list(doctor);
                break;             
              case 'school':
                list(school);
                break; 
            case 'worker':
                list(worker);
                break;
            default: //default child option is blank
                jq81("#child_selection").html('');  
                break;
           }
});

//function to populate child select box
function list(array_list)
{
    jq81("#child_selection").html(""); //reset child options
    jq81(array_list).each(function (i) { //populate child options
        jq81("#child_selection").append("<option value=\""+array_list[i].value+"\">"+array_list[i].display+"</option>");
    });
}

});

</script>

我看到更多有同样问题的人:

但是,我尝试了解决方案,但我无法弄清楚,我希望有人能帮助我

4

1 回答 1

0

您声明自定义脚本并添加 jquery,但它们必须分开:

<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>

+ 注意 jquery src url

编辑:此代码在我的 chrome 中运行良好

<html>
I am a </span><select name="parent_selection" id="parent_selection">
        <option value="">-- Please Select --</option>
        <option value="patient">Patient</option>
        <option value="doctor">Doctor or physician</option>
        <option value="school">School or parent</option>
        <option value="worker">Case worker</option>
    </select>
    <br /><span>and I need information on</span>
    <select name="child_selection" id="child_selection" onchange="location = this.options[this.selectedIndex].value;">
    </select>
</html>




<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>

var jq81 = jQuery.noConflict();
jq81(document).ready(function($){
//let's create arrays
var patient = [
    {display: "My initial visit", value: "patients#visit" },
    {display: "My initial evaluation", value: "patients#visit" },
    {display: "My appointments", value: "patients#appointments" },
    {display: "Your payment policies", value: "patients#policies" }];

var doctor = [
    {display: "Our approach", value: "doctors-and-physicians" },
    {display: "Our services", value: "services" },
    {display: "Referring patients", value: "patients#visit" }];

var school = [
    {display: "Our approach", value: "schools-and-parents" },
    {display: "My child's initial evaluation", value: "patients#visit" },
    {display: "Setting appointments", value: "patients#appointments" },
    {display: "Your payment policies", value: "patients#policies" }];

var worker = [
    {display: "Our approach", value: "case-workers" },
    {display: "Insurance policies", value: "clients#insurance" },
    {display: "Your Payment policies", value: "patients#policies" }];

//If parent option is changed
jq81("#parent_selection").change(function() {
    var parent = jq81(this).val(); //get option value from parent

    switch(parent){ //using switch compare selected option and populate child
          case 'patient':
            list(patient);
            break;
          case 'doctor':
            list(doctor);
            break;             
          case 'school':
            list(school);
            break; 
        case 'worker':
            list(worker);
            break;
        default: //default child option is blank
            jq81("#child_selection").html('');  
            break;
       }
});

//function to populate child select box
function list(array_list)
{
    jq81("#child_selection").html(""); //reset child options
    jq81(array_list).each(function (i) { //populate child options
    jq81("#child_selection").append("<option value=\""+array_list[i].value+"\">"+array_list[i].display+"</option>");
    });
}

});

</script>
于 2016-05-21T19:03:21.003 回答