2

这是一个很奇怪的问题，当我的程序向用户询问地址时，而不是等待输入，似乎完全跳过了getline()函数

Answerinput:

cout << "would you like to add another entry to the archive? (Y/N):";

cin >> answer;

cout << endl;
cout << endl;

answer = toupper(answer);


 switch(answer)
    {
    case 'Y':
        Entrynumber++;

        cout << "began record number " << Entrynumber << "+ 1." << endl;

        cout << "Enter the last name of the person to be entered" << endl;

        cin >> stringentry;
        cout << endl;

        stringlength = stringentry.length();

        strcpy(Record[Entrynumber].Last_Name, stringentry.c_str());


        Record[Entrynumber].Last_Name[stringlength] = '*';



        cout << "Enter the first name of the person" << endl;

        cin >> stringentry;
        cout << endl;

        stringlength = stringentry.length();

        strcpy(Record[Entrynumber].First_Name, stringentry.c_str());

        Record[Entrynumber].First_Name[stringlength] = '*';

        cout << "Enter the SSN of the person" << endl;
        cin >> Record[Entrynumber].SSN;
        cout << endl;

        cout << "Enter the age of the person" << endl;
        cin >> Record[Entrynumber].Age;
        cout << endl;

        cout << "Enter the address of the person" << endl;


        cin.getline(Record[Entrynumber].Address,70);


        cout << endl;


        stringentry = Record[Entrynumber].Address;

        stringlength = stringentry.length();



        Record[Entrynumber].Address[stringlength] = '*';

        cout << "you entered:" << endl;



        for(jim = 0 ; Record[Entrynumber].Last_Name[jim + 1] != '*' ; jim++)
        {
            cout << Record[Entrynumber].Last_Name[jim];
        }

        cout << ',' ;


        for(jim = 0 ; Record[Entrynumber].First_Name[jim + 1] != '*' ; jim++)
        {
            cout << Record[Entrynumber].First_Name[jim];
        }

        cout << endl;

        cout << Record[Entrynumber].SSN << endl;
        cout << Record[Entrynumber].Age << endl;

        for(jim = 0 ; Record[Entrynumber].Address[jim + 1] != '*' ; jim++)
        {
            cout << Record[Entrynumber].Address[jim];
        }
        cout << endl;
        cout << endl;


        goto Answerinput;
    case 'N':
        cout << "ok" << endl;
        break;
    default:
        cout << "invalid answer" << endl;
        goto Answerinput;
    }

输出到控制台

would you like to add another entry to
the archive? (Y/N):Y

began record number 6+ 1. 


 Enter the last name of the person to be entered 
 John


 Enter the first name of the person 
 John

 Enter the SSN of the person  22222222

 Enter the age of the person  22

 Enter the address of the person

 you entered: 
Joh,Joh 
22222222 
22
 *¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦
 //////////////22 more lines of'|'//////////////////////////////////////////////
 ... 
¦¦¦¦¦¦¦¦l3-j

 would you like to add another entry to the archive? (Y/N):

cin.getline() 和 getline() 都做同样的事情。

我正在使用 MVC++ 2008。

Record 数组中的所有字段都是结构体，Record[Entrynumber].Address 是一个 char 数组。

4

2 回答 2

3

Cin 可能将回车留在 getline 检索的缓冲区中。尝试

cin.ignore(1000, '\n');

cin.getline(Record[Entrynumber].Address,70);

>> 运算符在检索数据后不会删除换行符，但会在检索数据之前忽略前导空格，而 getline 只会检索其中的任何内容，并在读取后删除 '\n'，因为它是行的一部分'得到'。

于 2010-09-16T23:12:59.260 回答
3

鉴于您的 getline 首先读取的缓冲区中可能有剩余输入，我建议您在尝试输入下一个数据之前清除缓冲区：

std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
于 2010-09-16T23:13:33.367 回答