1

我有一个看起来像这样的数据框：

         cnt    bnk qst ans
1  Country 1 Bank 1  q1   1
2  Country 2 Bank 2  q1   1
3  Country 3 Bank 3  q1   3
4  Country 4 Bank 4  q1   1
5  Country 1 Bank 1  q2   1
6  Country 2 Bank 2  q2   2
7  Country 3 Bank 3  q2   3
8  Country 4 Bank 4  q2   4
9  Country 1 Bank 1  q3   1
10 Country 2 Bank 2  q3   1
11 Country 3 Bank 3  q3   2
12 Country 4 Bank 4  q3   1

供您参考，q' 代表“问题”。所以，q2是“问题2”。同样，ans是响应。

现在，我想根据中的响应创建一个分类变量q2。特别是我想分配以下类别：

  1. 上市
  2. 私人的
  3. 混合
  4. 其他

所以，如果ans=1to qst=q2，这是“Public”，如果ans=2toqst=q2这是“Private”等。所以，我之后的数据框应该是这样的：

         cnt    bnk qst ans   dummy
1  Country 1 Bank 1  q1   1  Public
2  Country 2 Bank 2  q1   1 Private
3  Country 3 Bank 3  q1   3   Mixed
4  Country 4 Bank 4  q1   1  Other'
5  Country 1 Bank 1  q2   1  Public
6  Country 2 Bank 2  q2   2 Private
7  Country 3 Bank 3  q2   3   Mixed
8  Country 4 Bank 4  q2   4  Other'
9  Country 1 Bank 1  q3   1  Public
10 Country 2 Bank 2  q3   1 Private
11 Country 3 Bank 3  q3   2   Mixed
12 Country 4 Bank 4  q3   1  Other'

我试图使用 ifelse，但我没有做我想做的事。有人可以给我一些建议吗？

数据

dput(df)
structure(list(cnt = c("Country 1", "Country 2", "Country 3", 
"Country 4", "Country 1", "Country 2", "Country 3", "Country 4", 
"Country 1", "Country 2", "Country 3", "Country 4"), bnk = c("Bank 1", 
"Bank 2", "Bank 3", "Bank 4", "Bank 1", "Bank 2", "Bank 3", "Bank 4", 
"Bank 1", "Bank 2", "Bank 3", "Bank 4"), qst = structure(c(1L, 
1L, 1L, 1L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L), .Label = c("q1", 
"q2", "q3"), class = "factor"), ans = c(1L, 1L, 3L, 1L, 1L, 2L, 
3L, 4L, 1L, 1L, 2L, 1L), dummy = c(NA, NA, NA, NA, "Public", 
"Private", "Mixed", "Other", NA, NA, NA, NA)), .Names = c("cnt", 
"bnk", "qst", "ans", "dummy"), row.names = c("1", "2", "3", "4", 
"5", "6", "7", "8", "9", "10", "11", "12"), class = "data.frame")
4

2 回答 2

1

以下将NA用于所有其他 Q，

df$dummy <- ifelse(df$ans == 1 & df$qst == 'q2', 'Public', 
               ifelse(df$ans == 2 & df$qst == 'q2', 'Private', 
                   ifelse(df$ans == 3 & df$qst == 'q2', 'Mixed', 
                        ifelse(df$ans == 4 & df$qst == 'q2', 'Other', NA))))

#         cnt    bnk qst ans   dummy
#1  Country 1 Bank 1  q1   1    <NA>
#2  Country 2 Bank 2  q1   1    <NA>
#3  Country 3 Bank 3  q1   3    <NA>
#4  Country 4 Bank 4  q1   1    <NA>
#5  Country 1 Bank 1  q2   1  Public
#6  Country 2 Bank 2  q2   2 Private
#7  Country 3 Bank 3  q2   3   Mixed
#8  Country 4 Bank 4  q2   4   Other
#9  Country 1 Bank 1  q3   1    <NA>
#10 Country 2 Bank 2  q3   1    <NA>
#11 Country 3 Bank 3  q3   2    <NA>
#12 Country 4 Bank 4  q3   1    <NA>
于 2016-05-18T14:44:03.210 回答
1

以下内容适用于名为 df 的 data.frame。没有数据很难测试：

# construct dummy variable in subset data.frame
dfCountryQ2 <- df[df$qst=="q2", c("cnt", "ans")]
dfCountryQ2$dummy <- factor(dfCountryQ2$ans, levels=1:4,
                            labels=c("Public", "Private", "Mixed", "Other"))

# merge on by country
df <- merge(df, dfCountryQ2[, c("cnt", "dummy")], by="cnt")
于 2016-05-18T14:50:42.187 回答