24

I am using xmlrpclib.ServerProxy to make RPC calls to a remote server. If there is not a network connection to the server it takes the default 10 seconds to return a socket.gaierror to my program.

This is annoying when doing development without a network connection, or if the remote server is down. Is there a way to update the timeout on my ServerProxy object?

I can't see a clear way to get access to the socket to update it.

4

9 回答 9

20

更直接的解决方案是： http: //www.devpicayune.com/entry/200609191448

import xmlrpclib 
import socket

x = xmlrpclib.ServerProxy('http:1.2.3.4')  
socket.setdefaulttimeout(10)        #set the timeout to 10 seconds 
x.func_name(args)                   #times out after 10 seconds
socket.setdefaulttimeout(None)      #sets the default back
于 2009-11-19T20:09:22.953 回答
18

干净的非全球版本。

import xmlrpclib
import httplib


class TimeoutHTTPConnection(httplib.HTTPConnection):
    def connect(self):
        httplib.HTTPConnection.connect(self)
        self.sock.settimeout(self.timeout)


class TimeoutHTTP(httplib.HTTP):
    _connection_class = TimeoutHTTPConnection

    def set_timeout(self, timeout):
        self._conn.timeout = timeout


class TimeoutTransport(xmlrpclib.Transport):
    def __init__(self, timeout=10, *l, **kw):
        xmlrpclib.Transport.__init__(self, *l, **kw)
        self.timeout = timeout

    def make_connection(self, host):
        conn = TimeoutHTTP(host)
        conn.set_timeout(self.timeout)
        return conn


class TimeoutServerProxy(xmlrpclib.ServerProxy):
    def __init__(self, uri, timeout=10, *l, **kw):
        kw['transport'] = TimeoutTransport(
            timeout=timeout, use_datetime=kw.get('use_datetime', 0))
        xmlrpclib.ServerProxy.__init__(self, uri, *l, **kw)


if __name__ == "__main__":
    s = TimeoutServerProxy('http://127.0.0.1:9090', timeout=2)
    s.dummy()
于 2010-01-22T11:10:29.617 回答
5

我想要一个小而干净但又明确的版本，所以根据这里的所有其他答案，这就是我想出的：

import xmlrpclib


class TimeoutTransport(xmlrpclib.Transport):

    def __init__(self, timeout, use_datetime=0):
        self.timeout = timeout
        # xmlrpclib uses old-style classes so we cannot use super()
        xmlrpclib.Transport.__init__(self, use_datetime)

    def make_connection(self, host):
        connection = xmlrpclib.Transport.make_connection(self, host)
        connection.timeout = self.timeout
        return connection


class TimeoutServerProxy(xmlrpclib.ServerProxy):

    def __init__(self, uri, timeout=10, transport=None, encoding=None, verbose=0, allow_none=0, use_datetime=0):
        t = TimeoutTransport(timeout)
        xmlrpclib.ServerProxy.__init__(self, uri, t, encoding, verbose, allow_none, use_datetime)


proxy = TimeoutServerProxy(some_url)

起初我没有意识到xmlrpclib有老式的类，所以我发现它对它的评论很有用，否则一切都应该是不言自明的。

我不明白为什么httplib.HTTP还必须进行子类化，如果有人可以就此启发我，请这样做。上述解决方案已尝试并有效。

于 2015-11-26T17:20:22.330 回答
2

这是适用于 Python 2.7 的代码（可能适用于 Python 的其他 2.x 版本）而不引发AttributeError，instance has no attribute 'getresponse'。


class TimeoutHTTPConnection(httplib.HTTPConnection):
    def connect(self):
        httplib.HTTPConnection.connect(self)
        self.sock.settimeout(self.timeout)

class TimeoutHTTP(httplib.HTTP):
    _connection_class = TimeoutHTTPConnection

    def set_timeout(self, timeout):
        self._conn.timeout = timeout

class TimeoutTransport(xmlrpclib.Transport):
    def __init__(self, timeout=socket._GLOBAL_DEFAULT_TIMEOUT, *args, **kwargs):
        xmlrpclib.Transport.__init__(self, *args, **kwargs)
        self.timeout = timeout

    def make_connection(self, host):
        if self._connection and host == self._connection[0]:
            return self._connection[1]

        chost, self._extra_headers, x509 = self.get_host_info(host)
        self._connection = host, httplib.HTTPConnection(chost)
        return self._connection[1]


transport = TimeoutTransport(timeout=timeout)
xmlrpclib.ServerProxy.__init__(self, uri, transport=transport, allow_none=True)
于 2011-10-27T11:46:37.323 回答
1

这是来自http://code.activestate.com/recipes/473878/的逐字副本

def timeout(func, args=(), kwargs={}, timeout_duration=1, default=None):
    import threading
    class InterruptableThread(threading.Thread):
        def __init__(self):
        threading.Thread.__init__(self)
        self.result = None

        def run(self):
            try:
                self.result = func(*args, **kwargs)
            except:
                self.result = default

    it = InterruptableThread()
    it.start()
    it.join(timeout_duration)
    if it.isAlive():
        return default
    else:
        return it.result
于 2008-12-17T15:53:56.157 回答
1

基于 antonylesuisse 的一个，但适用于 Python 2.7.5，解决了问题：AttributeError: TimeoutHTTP instance has no attribute 'getresponse'

class TimeoutHTTP(httplib.HTTP):
    def __init__(self, host='', port=None, strict=None,
                timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
        if port == 0:
            port = None
        self._setup(self._connection_class(host, port, strict, timeout))

    def getresponse(self, *args, **kw):
        return self._conn.getresponse(*args, **kw)

class TimeoutTransport(xmlrpclib.Transport):
    def __init__(self,  timeout=socket._GLOBAL_DEFAULT_TIMEOUT, *l, **kw):
        xmlrpclib.Transport.__init__(self, *l, **kw)
        self.timeout=timeout

    def make_connection(self, host):
        host, extra_headers, x509 = self.get_host_info(host)
        conn = TimeoutHTTP(host, timeout=self.timeout)
        return conn

class TimeoutServerProxy(xmlrpclib.ServerProxy):
    def __init__(self, uri, timeout= socket._GLOBAL_DEFAULT_TIMEOUT, *l, **kw):
        kw['transport']=TimeoutTransport(timeout=timeout, use_datetime=kw.get('use_datetime',0))
        xmlrpclib.ServerProxy.__init__(self, uri, *l, **kw)

proxy = TimeoutServerProxy('http://127.0.0.1:1989', timeout=30)
print proxy.test_connection()
于 2014-11-06T07:58:16.107 回答
1

基于来自 antonylesuisse 的工作版本（在 python >= 2.6 上）。

# -*- coding: utf8 -*-
import xmlrpclib
import httplib
import socket

class TimeoutHTTP(httplib.HTTP):
   def __init__(self, host='', port=None, strict=None,
                timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
        if port == 0:
            port = None
        self._setup(self._connection_class(host, port, strict, timeout))

class TimeoutTransport(xmlrpclib.Transport):
    def __init__(self, timeout=socket._GLOBAL_DEFAULT_TIMEOUT, *args, **kwargs):
        xmlrpclib.Transport.__init__(self, *args, **kwargs)
        self.timeout = timeout

    def make_connection(self, host):
        host, extra_headers, x509 = self.get_host_info(host)
        conn = TimeoutHTTP(host, timeout=self.timeout)
        return conn

class TimeoutServerProxy(xmlrpclib.ServerProxy):
    def __init__(self, uri, timeout=socket._GLOBAL_DEFAULT_TIMEOUT,
                 *args, **kwargs):
        kwargs['transport'] = TimeoutTransport(timeout=timeout,
                                    use_datetime=kwargs.get('use_datetime', 0))
        xmlrpclib.ServerProxy.__init__(self, uri, *args, **kwargs)
于 2010-01-26T10:15:16.033 回答
0

以下示例适用于 Python 2.7.4。

import xmlrpclib
from xmlrpclib import *
import httplib

def Server(url, *args, **kwargs):
    t = TimeoutTransport(kwargs.get('timeout', 20))
    if 'timeout' in kwargs:
       del kwargs['timeout']
    kwargs['transport'] = t
    server = xmlrpclib.Server(url, *args, **kwargs)
    return server

TimeoutServerProxy = Server

class TimeoutTransport(xmlrpclib.Transport):

    def __init__(self, timeout, use_datetime=0):
        self.timeout = timeout
        return xmlrpclib.Transport.__init__(self, use_datetime)

    def make_connection(self, host):
        conn = xmlrpclib.Transport.make_connection(self, host)
        conn.timeout = self.timeout
        return connrpclib.Server(url, *args, **kwargs)
于 2013-04-12T10:36:02.727 回答
0

这是另一个使用 Python语句的智能且非常Pythonic的解决方案：with

import socket
import xmlrpc.client

class MyServerProxy:
    def __init__(self, url, timeout=None):
        self.__url = url
        self.__timeout = timeout
        self.__prevDefaultTimeout = None

    def __enter__(self):
        try:
            if self.__timeout:
                self.__prevDefaultTimeout = socket.getdefaulttimeout()
                socket.setdefaulttimeout(self.__timeout)
            proxy = xmlrpc.client.ServerProxy(self.__url, allow_none=True)
        except Exception as ex:
            raise Exception("Unable create XMLRPC-proxy for url '%s': %s" % (self.__url, ex))
        return proxy
    def __exit__(self, type, value, traceback):
        if self.__prevDefaultTimeout is None:
            socket.setdefaulttimeout(self.__prevDefaultTimeout)

这个类可以这样使用：

with MyServerProxy('http://1.2.3.4', 20) as proxy:
    proxy.dummy()
于 2013-01-18T11:05:39.927 回答