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我有一组不相交的动态编写的类，我想单独编译（并修复编译错误）。然后我想将它们组合到同一个程序集中。由于它们已经被编译，我不想简单地将它们的语法树传递给程序集编译（以避免编译两次）。我试图将它们编译成 netmodules，然后使用这些 netmodules 作为对程序集的引用，但生成的程序集没有所需的类型。

这是我的测试代码（非常类似于 Roslyn 的 CompilationEmitTests.MultipleNetmodulesWithPrivateImplementationDetails()）

public static class Program
{

    public static void Main()
    {
        var s1 = @"public class A {internal object o1 = new { hello = 1, world = 2 }; public static string M1() {    return ""Hello, "";}}";
        var s2 = @"public class B : A{internal object o2 = new { hello = 1, world = 2 };public static string M2(){    return ""world!"";}}";
        var s3 = @"public class Program{public static void Main(){    System.Console.Write(A.M1());    System.Console.WriteLine(B.M2());}}";
        var comp1 = CreateCompilationWithMscorlib("a1", s1, compilerOptions: TestOptions.ReleaseModule);
        var ref1 = comp1.EmitToImageReference();

        var comp2 = CreateCompilationWithMscorlib("a2", s2, compilerOptions: TestOptions.ReleaseModule, references: new[] { ref1 });
        var ref2 = comp2.EmitToImageReference();

        var comp3 = CreateCompilationWithMscorlib("a3", s3, compilerOptions: TestOptions.ReleaseExe.WithModuleName("C"), references: new[] { ref1, ref2 });

        var ref3 = comp3.EmitToImageReference();

        IEnumerable<byte> result = comp3.EmitToArray();

        Assembly assembly = Assembly.Load(result.ToArray());

        Module module = assembly.GetModule("C");

        Type prog = module.GetType("Program");

        object instance = Activator.CreateInstance(prog);

        MethodInfo method = prog.GetMethod("Main");

        method.Invoke(null, null);
    }

    public static ImmutableArray<byte> ToImmutable(this MemoryStream stream)
    {
        return ImmutableArray.Create<byte>(stream.ToArray());
    }

    internal static ImmutableArray<byte> EmitToArray
    (
        this Compilation compilation,
        EmitOptions options = null,
        Stream pdbStream = null
    )
    {
        var stream = new MemoryStream();

        if (pdbStream == null && compilation.Options.OptimizationLevel == OptimizationLevel.Debug)
        {
            pdbStream = new MemoryStream();
        }

        var emitResult = compilation.Emit(
            peStream: stream,
            pdbStream: pdbStream,
            xmlDocumentationStream: null,
            win32Resources: null,
            manifestResources: null,
            options: options);

        return stream.ToImmutable();
    }
    public static MetadataReference EmitToImageReference(
        this Compilation comp
    )
    {
        var image = comp.EmitToArray();
        if (comp.Options.OutputKind == OutputKind.NetModule)
        {
            return ModuleMetadata.CreateFromImage(image).GetReference(display: comp.AssemblyName);
        }
        else
        {
            return AssemblyMetadata.CreateFromImage(image).GetReference(display: comp.AssemblyName);
        }
    }

    private static CSharpCompilation CreateCompilationWithMscorlib(string assemblyName, string code, CSharpCompilationOptions compilerOptions = null, IEnumerable<MetadataReference> references = null)
    {
        SourceText sourceText = SourceText.From(code, Encoding.UTF8);
        SyntaxTree syntaxTree = SyntaxFactory.ParseSyntaxTree(sourceText, null, "");

        MetadataReference mscoreLibReference = AssemblyMetadata.CreateFromFile(typeof(string).Assembly.Location).GetReference();

        IEnumerable<MetadataReference> allReferences = new MetadataReference[] { mscoreLibReference };

        if (references != null)
        {
            allReferences = allReferences.Concat(references);
        }

        CSharpCompilation compilation = CSharpCompilation.Create
        (
            assemblyName,
            new[] {syntaxTree},
            options : compilerOptions,
            references: allReferences
        );

        return compilation;
    }

}

Main() 在静态方法 Invoke() 处引发异常，因为它找不到对 A 和 B 类的引用。

我究竟做错了什么？

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1 回答 1

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这是用户 0xd4d 在 Github 上针对相同问题发布的答案。我测试了它是否有效：

您必须在需要访问网络模块之前调用 LoadModule

assembly.LoadModule("a1.netmodule", a1_netmodule_bytes);
assembly.LoadModule("a2.netmodule", a2_netmodule_bytes);

如果您已将它们全部保存到磁盘，则无需执行此操作。

我仍然不明白他说如果我将它保存到磁盘我不需要这样做是什么意思。

于 2016-05-15T14:45:48.717 回答