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我已经开发了一个android通过 wifi 遥控汽车的应用程序。为此我使用了esp8266 nodemcuwifi 模块。在我的应用程序中。有前进、后退、右、左四个按钮。我可以通过 wifi 连接这个模块并为 ex 做一些基本的操作。前进，后退，右转，左转。以下是执行此操作的代码：

 @Override
public boolean onTouch(View v, MotionEvent event) {
    String action;

    if (v.getId() == moveForward.getId())
        action = "/forward/";

    else if (v.getId() == moveReverse.getId())
        action = "/reverse/";

    else if (v.getId() == moveRigth.getId())
        action = "/right/";

    else
        action = "/left/";

    String serverAddress = ipAddress.getText().toString() + ":" + "80" + action;

    if (event.getAction() == MotionEvent.ACTION_DOWN) {
        HttpRequestTask requestTask = new HttpRequestTask(serverAddress);
        requestTask.execute("1");

    } else if (event.getAction() == MotionEvent.ACTION_UP) {
        HttpRequestTask requestTask = new HttpRequestTask(serverAddress);
        requestTask.execute("0");
    }
    return false;
}

 private class HttpRequestTask extends AsyncTask<String, Void, String> {

    private String serverAdress;
    private String serverResponse = "";

    public HttpRequestTask(String serverAdress) {
        this.serverAdress = serverAdress;
    }

    @Override
    protected String doInBackground(String... params) {

        String val = params[0];
        String url = "http://" + serverAdress + val;
        Log.e("url", url);

        try {
            HttpClient client = new DefaultHttpClient();
            HttpGet getRequest = new HttpGet();
            getRequest.setURI(new URI(url));
            HttpResponse response = client.execute(getRequest);

            InputStream inputStream = null;
            inputStream = response.getEntity().getContent();
            BufferedReader bufferedReader =
                    new BufferedReader(new InputStreamReader(inputStream));

            serverResponse = bufferedReader.readLine();
            inputStream.close();

        } catch (URISyntaxException e) {
            e.printStackTrace();
            serverResponse = e.getMessage();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
            serverResponse = e.getMessage();
        } catch (IOException e) {
            e.printStackTrace();
            serverResponse = e.getMessage();
        }

        return serverResponse;
    }

当用户向前按下时，也可以按下右键或左键，小车同时前进右转或倒车左转。但是我无法在代码中同时处理两个按钮按下事件。你能告诉我一个方法吗？

4

1 回答 1

0 
 if (v.getId() == moveForward.getId())
        action = "/forward/";

 if (v.getId() == moveReverse.getId())
        action = "/reverse/";

 if (v.getId() == moveRigth.getId())
        action = "/right/";

 if (v.getId() == moveLeft.getId())
        action = "/left/";

所以你可以处理所有的动作，你的旧代码将只测试一个条件

于 2016-05-10T22:34:06.463 回答