3

我正在研究 c# 中的函数式编程,这样我就可以减少代码中的副作用数量,并使测试更容易并泛化我的代码,从而使重构变得更容易。但是,我在弄清楚如何using使用通用 using 块嵌套语句时遇到问题。考虑以下:

public static class Disposable
{
    public static TResult Using<TDisposable, TResult>
    (
      Func<TDisposable> factory,
      Func<TDisposable, TResult> fn) where TDisposable : IDisposable
      {
            using (var disposable = factory())
            {
                return fn(disposable);
            }
      }
}

我使用以下代码示例调用此代码:

Disposable.Using(
               StreamFactory.GetStream,
               stream => new byte[stream.Length].Tee(b => stream.Read(b, 0, (int)stream.Length)))

我将这个修改后的using语句的输出传递给管道中的另一个方法。

然而,我确实遇到了一个警告,我被卡住了。

如果我想使用嵌套的 using 语句,但对我想要传递的返回项进行修改怎么办?

Disposable通过重用我上面存根的类来考虑以下内容:

        Disposable.Using(
            () => new PasswordDeriveBytes(PasswordConstants.CryptoKey, null),
            password => Disposable.Using(
                () => new RijndaelManaged(),
                symmetricKey =>
                    Disposable.Using(
                        () => symmetricKey.CreateEncryptor(password.GetBytes(PasswordConstants.KeySize/8), Encoding.ASCII.GetBytes(PasswordConstants.Cipher)),
                        encryptor => encryptor)
                ));

此代码有效...但是,如果我想更改symmetricKey's加密模式怎么办?

以下不起作用:

        Disposable.Using(
                () => new PasswordDeriveBytes(PasswordConstants.CryptoKey, null),
                password => Disposable.Using(
                    () => new RijndaelManaged(),
                    symmetricKey =>
                        {
                            symmetricKey.Mode = CipherMode.CBC; // ← this causes an issue, and also the fact that I made a **code block** here
                            Disposable.Using(
                                () => symmetricKey.CreateEncryptor(password.GetBytes(PasswordConstants.KeySize/8), Encoding.ASCII.GetBytes(PasswordConstants.Cipher)),
                                encryptor => encryptor);
                        }
                    ));

我能做些什么来允许修改通过Disposable.Using我上面创建的通用方法传递的变量?

4

2 回答 2

3

如果我想使用嵌套的 using 语句,但对我想要传递的返回项进行修改怎么办?

让我们从简化您的 开始Disposable.Using,我们不需要泛型TDisposable- 删除它并使用IDisposable.

public static class Disposable
{
    public static TResult Using<TResult>(
        Func<IDisposable> factory,
        Func<IDisposable, TResult> use)
   {
        using (var disposable = factory())
        {
             return use(disposable);
        }
   }
}

此外,正如@juharr 所提醒的那样 - 你错过了一个return

Disposable.Using(
        () => new PasswordDeriveBytes(PasswordConstants.CryptoKey, null),
        password => Disposable.Using(
            () => new RijndaelManaged(),
            symmetricKey =>
            {
                symmetricKey.Mode = CipherMode.CBC; 
                return Disposable.Using(
                    () => symmetricKey.CreateEncryptor(password.GetBytes(PasswordConstants.KeySize/8), Encoding.ASCII.GetBytes(PasswordConstants.Cipher)),
                    encryptor => encryptor);
            }));

这是由于函数和方法之间的细微差别。lambdaanonymous

于 2016-05-10T13:20:30.613 回答
2

我认为您只是缺少一个return. 尝试这个。

Disposable.Using(
    () => new PasswordDeriveBytes(PasswordConstants.CryptoKey, null),
    password => Disposable.Using(
        () => new RijndaelManaged(),
        symmetricKey =>
        {
            symmetricKey.Mode = CipherMode.CBC; 
            return Disposable.Using(
                () => symmetricKey.CreateEncryptor(password.GetBytes(PasswordConstants.KeySize/8), Encoding.ASCII.GetBytes(PasswordConstants.Cipher)),
                encryptor => encryptor);
        }));
于 2016-05-10T13:18:27.640 回答