1

如何仅提取字符串之后CX_EduDegree=???????并%20用空格替换。数据由空格分隔，并且从不在同一位置。

我试图将 patindex 与子字符串一起使用并替换。但我没有成功。

select top 5 clientid, extFields
from tblSYS_Clients
where ExtFields like '%CX_Edu%'
and ClientID in ('1633496','1633692','1453977','1657410','1584563','1655341','1632686','1352611','1484271','1361354') 

clientid    extFields
1352611 CX_CurrentJobStartDate=01/20/2001  CX_CurrentJobHours=40  CX_SupervisorName=Rhonda%20Kaiser  CX_EduDegree=BS%20in%20Nursing  CX_SupervisorPhone=970-495-8100
1361354 CX_CurrentJobStartDate=06/20/1997  CX_CurrentJobHours=30  CX_SupervisorName=Georgia%20Chapin  CX_SupervisorPhone=702-616-5632  CX_EduDegree=MS/MA%20%20in%20Nursing
1453977 CX_CurrentJobStartDate=08/20/1990  CX_CurrentJobHours=40  CX_SupervisorName=Jan%20Rasco  CX_SupervisorPhone=281-631-8789  CX_EduDegree=Diploma
1484271 CX_CurrentJobStartDate=01/01/2011  CX_CurrentJobHours=40  CX_SupervisorName=Kay%20Hix  CX_SupervisorPhone=317-329-7209  CX_EduDegree=AD%20in%20Nursing
1584563 CX_CurrentJobStartDate=11/26/2006  CX_CurrentJobHours=40  CX_SupervisorName=PHILLIP%20MOISUK  CX_SupervisorPhone=916-453-4545  CX_EduDegree=BS%20in%20Nursing

我想看到的结果：

1633496 BS in Nursing 
1633692 BS in Nursing 
1453977 Diploma 
1657410 AD in Nursing 
1584563 BS in Nursing 
1655341 AD in Nursing 
1632686 BS in Nursing 
1352611 BS in Nursing 
1484271 AD in Nursing 
1361354 MS/MA in Nursing
4

4 回答 4

0

使用和charindex的组合。如果总是出现在字符串的末尾，这将起作用。reversesubstringCX_EduDegree=

带有示例数据的演示

select clientid,
substring(
          extfields
          ,charindex('CX_EduDegree=',extFields)+len('CX_EduDegree=')
          ,charindex(' ',extFields)
         ) as extfield
from tblSYS_Clients
where ExtFields like '%CX_Edu%'
and ClientID in ('1633496','1633692','1453977','1657410','1584563','1655341','1632686','1352611','1484271','1361354')
于 2016-05-09T23:22:28.090 回答
0

SQL Server 中的字符串操作有点麻烦。我喜欢这样做outer apply：

select c.clientid, c.extFields, x2.x2
from tblSYS_Clients c outer apply
     (select stuff(c.ExtFields, 1, charindex('CX_edu', c.ExtFields), '') as x1
     ) x outer apply
     (select replace(left(x.x1, charindex(' ', x1)), '%20', ' ') as x2
     ) x2
where c.ExtFields like '%CX_Edu%' and
      c.ClientID in ('1633496', '1633692', '1453977', '1657410', '1584563', '1655341', '1632686', '1352611', '1484271', '1361354') ;

注意：我认为上述方法会起作用。SQL Server 不保证where在子查询之前处理outer apply。实际上，我认为确实如此，因此完成过滤以确保子字符串位于ExtFields. 如果不是，这可以很容易地使用 来解决case，但这会使答案变得有点复杂。

于 2016-05-09T23:19:01.053 回答
0

一种使用 XML 数据类型的方法

SELECT  clientid,
        REPLACE(t.cx.value('(r/@CX_EduDegree)[1]', 'varchar(100)'),'%20',' ') AS degree
FROM    (
    SELECT  clientid, 
            CAST('<r ' + REPLACE(REPLACE(extFields,'=','="') , '  ','"/><r ') + '"></r>') AS XML) cx
    FROM    tblSYS_Clients
    WHERE   clientid in ('1633496','1633692','1453977','1657410','1584563','1655341','1632686','1352611','1484271','1361354') 
) t

与字符串操作查询相比，xml 相当慢。

你可以做的另一件事是使用一个字符串拆分器，比如这里的一个

这是使用 Jeff Moden 的 DelimitedSplit8K 函数的示例。

SELECT  t1.clientid,
        REPLACE(t2.Item,'CX_EduDegree=','')
FROM    tblSYS_Clients t1
        CROSS APPLY (
            SELECT REPLACE(t.Item, '%20', ' ') Item 
            FROM dbo.DelimitedSplit8K(t1.extFields, '  ') t 
            WHERE t.Item LIKE 'CX_EduDegree%' 
        ) t2
WHERE   clientid in ('1633496','1633692','1453977','1657410','1584563','1655341','1632686','1352611','1484271','1361354')

仍然不如这里的其他一些快，但可能更容易理解或让您更容易获得其他领域。

于 2016-05-10T01:05:24.787 回答
0

使用这个结构：

select clientid, replace(SUBSTRING(extFields,
   PATINDEX('%CX_EduDegree=%',extFields)+13,
      charindex(' ', extFields+' ',
          PATINDEX('%CX_EduDegree=%',extFields)) - 
             PATINDEX('%CX_EduDegree=%',extFields) - 13),'%20',' ') ex 
from  
(values 
(1352611, 'CX_CurrentJobStartDate=01/20/2001  CX_CurrentJobHours=40  CX_SupervisorName=Rhonda%20Kaiser  CX_EduDegree=BS%20in%20Nursing  CX_SupervisorPhone=970-495-8100'), 
(1361354, 'CX_CurrentJobStartDate=06/20/1997  CX_CurrentJobHours=30  CX_SupervisorName=Georgia%20Chapin  CX_SupervisorPhone=702-616-5632  CX_EduDegree=MS/MA%20%20in%20Nursing'), 
(1453977, 'CX_CurrentJobStartDate=08/20/1990  CX_CurrentJobHours=40  CX_SupervisorName=Jan%20Rasco  CX_SupervisorPhone=281-631-8789  CX_EduDegree=Diploma'), 
(1484271, 'CX_CurrentJobStartDate=01/01/2011  CX_CurrentJobHours=40  CX_SupervisorName=Kay%20Hix  CX_SupervisorPhone=317-329-7209  CX_EduDegree=AD%20in%20Nursing'), 
(1584563, 'CX_CurrentJobStartDate=11/26/2006  CX_CurrentJobHours=40  CX_SupervisorName=PHILLIP%20MOISUK  CX_SupervisorPhone=916-453-4545  CX_EduDegree=BS%20in%20Nursing') 
) t(clientid,    extFields)

结果：

clientid    ex
1352611 BS in Nursing
1361354 MS/MA  in Nursing
1453977 Diploma
1484271 AD in Nursing
1584563 BS in Nursing

代码中的一些注释以便更好地理解。正如你所看到charindex的作品。结果是一样的。

select clientid, 
replace(
SUBSTRING(extFields,--string to work with
   charindex('CX_EduDegree=',extFields)+13, --start position; 13 is length of CX_EduDegree=
      charindex(' ', extFields+' ', --searching end position +' ' to make sure that space exists
          charindex('CX_EduDegree=',extFields) -- start searching ' ' after this position
          ) --end position found
             - charindex('CX_EduDegree=',extFields) - 13) -- calculate length
             ,'%20',' ') ex --final touch - remove ugly %20 
from  
(values 
(1352611, 'CX_CurrentJobStartDate=01/20/2001  CX_CurrentJobHours=40  CX_SupervisorName=Rhonda%20Kaiser  CX_EduDegree=BS%20in%20Nursing  CX_SupervisorPhone=970-495-8100'), 
(1361354, 'CX_CurrentJobStartDate=06/20/1997  CX_CurrentJobHours=30  CX_SupervisorName=Georgia%20Chapin  CX_SupervisorPhone=702-616-5632  CX_EduDegree=MS/MA%20%20in%20Nursing'), 
(1453977, 'CX_CurrentJobStartDate=08/20/1990  CX_CurrentJobHours=40  CX_SupervisorName=Jan%20Rasco  CX_SupervisorPhone=281-631-8789  CX_EduDegree=Diploma'), 
(1484271, 'CX_CurrentJobStartDate=01/01/2011  CX_CurrentJobHours=40  CX_SupervisorName=Kay%20Hix  CX_SupervisorPhone=317-329-7209  CX_EduDegree=AD%20in%20Nursing'), 
(1584563, 'CX_CurrentJobStartDate=11/26/2006  CX_CurrentJobHours=40  CX_SupervisorName=PHILLIP%20MOISUK  CX_SupervisorPhone=916-453-4545  CX_EduDegree=BS%20in%20Nursing') 
) t(clientid,    extFields)

你觉得这个解决方案可以接受吗？

于 2016-05-09T23:42:08.470 回答