好的大家,我知道骑士的巡回赛问题在所有 cs 学生中都很流行,我无法让我的工作。我使用这种递归算法来进行移动,但是,一旦我到达移动 50 左右,我必须回溯,因为没有可用的移动,我最终永远无法完成巡回演出。我传递了一个 ChessNode(保存诸如节点是否已被访问、移动它是否被访问等内容)、下一行、下一列和前一个节点的移动计数。
private int moveRecur(ChessNode current, int row, int column, int moveV){
current.moveVisited = moveV+1;
if(current.moveVisited > 63){
return 0;
}
if(current.position==13 && aboard[row-1][column+2].visited != 1){
current.visited = 1;
moveRecur(aboard[row-1][column+2], row-1, column+2, current.moveVisited);
}
else if(current.position==22 && aboard[row-2][column+1].visited != 1){
current.visited = 1;
moveRecur(aboard[row-2][column+1], row-2, column+1, current.moveVisited);
}
else if(current.position == 50 && aboard[row+1][column-2].visited != 1){
current.visited = 1;
moveRecur(aboard[row+1][column-2], row+1, column-2, current.moveVisited);
}
else if(current.position == 41 && aboard[row+2][column-1].visited != 1){
current.visited =1;
moveRecur(aboard[row+2][column-1], row+2, column-1, current.moveVisited);
}
else if(current.position == 46 && aboard[row+2][column+1].visited != 1){
current.visited = 1;
moveRecur(aboard[row+2][column+1], row+2, column+1, current.moveVisited);
}
else if(current.position == 53 && aboard[row+1][column+2].visited != 1){
current.visited = 1;
moveRecur(aboard[row+1][column+2], row+1, column+2, current.moveVisited);
}
else if(current.position == 10 && aboard[row-1][column-2].visited != 1){
current.visited = 1;
moveRecur(aboard[row-1][column-2], row-1, column-2, current.moveVisited);
}
else if (current.position == 17 && aboard[row-2][column-1].visited != 1){
current.visited =1;
moveRecur(aboard[row-2][column-1], row-2, column-2, current.moveVisited);
}
if(row+1>=0 && row+1<8 && column+2>=0 && column+2<8){
if(aboard[row+1][column+2].visited != 1){
current.visited = 1;
moveRecur(aboard[row+1][column+2], row+1, column+2, current.moveVisited);
}
}
if(row+2>=0 && row+2<8 && column+1>=0 && column+1<8){
if(aboard[row+2][column+1].visited != 1){
current.visited = 1;
moveRecur(aboard[row+2][column+1], row+2, column+1, current.moveVisited);
}
}
if(row-1>=0 && row-1<8 && column-2>=0 && column-2<8){
if(aboard[row-1][column-2].visited != 1){
current.visited = 1;
moveRecur(aboard[row-1][column-2], row-1, column-2, current.moveVisited);
}
}
if(row-2>=0 && row-2<8 && column-1>=0 && column-1<8){
if(aboard[row-2][column-1].visited != 1){
current.visited = 1;
moveRecur(aboard[row-2][column-1], row-2, column-1, current.moveVisited);
}
}
if(row+1>=0 && row+1<8 && column-2>=0 && column-2<8){
if(aboard[row+1][column-2].visited != 1){
current.visited = 1;
moveRecur(aboard[row+1][column-2], row+1, column-2, current.moveVisited);
}
}
if(row+2>=0 && row+2<8 && column-1>=0 && column-1<8){
if(aboard[row+2][column-1].visited != 1){
current.visited = 1;
moveRecur(aboard[row+2][column-1], row+2, column-1, current.moveVisited);
}
}
if(row-1>=0 && row-1<8 && column+2>=0 && column+2<8){
if(aboard[row-1][column+2].visited != 1){
current.visited = 1;
moveRecur(aboard[row-1][column+2], row-1, column+2, current.moveVisited);
}
}
if(row-2>=0 && row-2<8 && column+1>=0 && column+1<8){
if(aboard[row-2][column+1].visited != 1){
current.visited = 1;
moveRecur(aboard[row-2][column+1], row-2, column+1, current.moveVisited);
}
}
//System.out.println(current.position + " "+current.moveVisited);
current.visited = 0;
return 0;
}
所以,最初我检查可以移动到角板位置的点,然后我只是根据可用的移动进行递归调用。所以我想我的主要问题是我做错了什么?或者我可以使用其他条件使游览更直观一些吗?
提前致谢!