2

我找到了一种不带参数调用 unix 外部命令的方法（例如“ls”、“pwd”）。它是这样的：

//Child process
char cwd[1024];
getcwd(cwd, sizeof(cwd));
char *argv[] = {*args, NULL}//(ex.) {"ls", NULL}
char *env[] = {cwd, NULL};
//concat():method that connects 2 strings
char *command_source = concat("/bin/", *args);
execve(command_source, argv, env);
return 0;

我正在尝试转换此代码以接受带有“ls -l”等参数的外部命令

4

2 回答 2

1

假设您知道参数的数量args并且它是argcs：

...
char **argv = calloc(sizeof(char*), argcs+1); 
for (int i=0; i<argcs; i++) 
    argv[i]=args[i]; 
argv[argcs]=NULL; 
...

如果没有，您可以argcs通过遍历数组搜索结束 NULL 轻松确定。

于 2016-05-07T22:58:52.337 回答
0

您也可以制作管道；查看命令是如何构建的并查看结构，它们是以 0 结尾的数组并且引号被剥离：

/*  who | awk '{print $1}' | sort | uniq -c | sort -n */
/*static char *cmd0[] = {"who", 0};
static char *cmd1[] = {"awk", "{print $1}", 0};
static char *cmd2[] = {"sort", 0};
static char *cmd3[] = {"uniq", "-c", 0};
static char *cmd4[] = {"sort", "-n", 0};*/

当您创建带有参数的管道时，这里有一些实用函数。它们经过了良好的测试并且没有错误。

管道.c

#define _XOPEN_SOURCE 500
/* One way to create a pipeline of N processes */

#ifndef STDERR_H_INCLUDED
#define STDERR_H_INCLUDED

static void err_sysexit(char const *fmt, ...);

static void err_syswarn(char const *fmt, ...);

#endif /* STDERR_H_INCLUDED */

/* pipeline.c */
#include <assert.h>
#include <stdio.h>
#include <string.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdlib.h>
#include "openshell.h"
#include <errno.h>

/* exec_nth_command() and exec_pipe_command() are mutually recursive */
static void exec_pipe_command(int ncmds, char ***cmds, Pipe output);

/* With the standard output plumbing sorted, execute Nth command */
static void exec_nth_command(int ncmds, char ***cmds) {
    assert(ncmds >= 1);
    if (ncmds > 1) {
        pid_t pid;
        Pipe input;
        if (pipe(input) != 0)
            err_sysexit("Failed to create pipe");
        if ((pid = fork()) < 0)
            err_sysexit("Failed to fork");
        if (pid == 0) {
            /* Child */
            exec_pipe_command(ncmds - 1, cmds, input);
        }
        /* Fix standard input to read end of pipe */
        dup2(input[0], 0);
        close(input[0]);
        close(input[1]);
    }
    execvp(cmds[ncmds - 1][0], cmds[ncmds - 1]);
    err_sysexit("Failed to exec %s", cmds[ncmds - 1][0]);
    /*NOTREACHED*/
}

/* Given pipe, plumb it to standard output, then execute Nth command */
static void exec_pipe_command(int ncmds, char ***cmds, Pipe output) {
    assert(ncmds >= 1);
    /* Fix stdout to write end of pipe */
    dup2(output[1], 1);
    close(output[0]);
    close(output[1]);
    exec_nth_command(ncmds, cmds);
}


/*  who | awk '{print $1}' | sort | uniq -c | sort -n */
/*static char *cmd0[] = {"who", 0};
static char *cmd1[] = {"awk", "{print $1}", 0};
static char *cmd2[] = {"sort", 0};
static char *cmd3[] = {"uniq", "-c", 0};
static char *cmd4[] = {"sort", "-n", 0};*/

/*static char **cmds[] = {cmd0, cmd1, cmd2, cmd3, cmd4};*/
/*static int ncmds = sizeof(cmds) / sizeof(cmds[0]);*/

/* Execute the N commands in the pipeline */
void exec_pipeline(int ncmds, char ***cmds) {
    assert(ncmds >= 1);
    pid_t pid;
    if ((pid = fork()) < 0)
        err_syswarn("Failed to fork");
    if (pid != 0)
        return;
    exec_nth_command(ncmds, cmds);
}

#include <stdarg.h>

static const char *arg0 = "<undefined>";

static void err_vsyswarn(char const *fmt, va_list args) {
    int errnum = errno;
    fprintf(stderr, "%s:%d: ", arg0, (int) getpid());
    vfprintf(stderr, fmt, args);
    if (errnum != 0)
        fprintf(stderr, " (%d: %s)", errnum, strerror(errnum));
    putc('\n', stderr);
}

static void err_syswarn(char const *fmt, ...) {
    va_list args;
    va_start(args, fmt);
    err_vsyswarn(fmt, args);
    va_end(args);
}

static void err_sysexit(char const *fmt, ...) {
    va_list args;
    va_start(args, fmt);
    err_vsyswarn(fmt, args);
    va_end(args);
    exit(1);
}

该代码来自先前问题的先前 shell 项目，在该问题中，上述代码获得了赏金。已经有一个详细的答案 - How to fix these errors in my code。C minishell也有较早的答案：添加包含大部分引用代码的管道。

您还可以阅读pipe(2)、pipe(7)和Advanced Linux Programming

于 2016-05-07T23:38:44.507 回答