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我想将我的论坛分组，如下所示：

在此处输入图像描述

我目前有一个名为的数据库表forum_categories，它带有一个标题并为创建的所有类别创建一个 ID。我还在数据库表中有一个名为forum_forums（我想要分类的所有不同论坛）的列，它采用名为category_apart_of.

我将如何在正确的类别 ID 中列出论坛？

太感谢了！

如果您想查看我的任何代码，或者希望我更深入地解释任何内容，请告诉我。

我当前列出论坛的代码（注意：获取所有论坛的 SQL 查询在上面）：

<thead>
    <tr>
      <th style="width: 50%;">Forum</th>   
      <th style="width: 10%;">Threads</th> 
      <th style="width: 10%;">Posts</th>
      <th style="width: 30%;">Latest Posts</th>        
    </tr>
    </thead>
    <tbody> 
    <?php 
      while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
        $forumID = $row['forumID'];
        $forum_title[] = $row['forum_title'];
        $forum_description[] = $row['forum_description'];
        $forum_total_threads[] = $row['forum_total_threads'];
        $forum_total_posts[] = $row['forum_total_posts'];
        $forum_latest_thread[] = $row['forum_latest_thread'];

        $stmt2 = $db->prepare("SELECT * FROM forum_threads WHERE forum_thread_belongs_to = '$forumID'");
        $stmt2->execute();
        $count = $stmt2->rowCount();

        echo '
        <tr><td><h4 style="margin-bottom: 0px;"><a style="margin-bottom: 0px;" href="forum.php?id=' 
        . $row['forumID'] . ' ">'.$row['forum_title']
        . '</a></h4><br /><h6 style="margin-bottom: 0px; margin-top: 0px;">'
        .$row['forum_description'].'</h6></td><td style="text-align: center;><span">'.$count
        .'</span></td><td style="text-align: center;><span">'.$row['forum_total_posts']
        .'</span></td><td>'.$row['forum_latest_thread'].'</td></tr>
        ';
     }
    ?>
</tbody>

两个表的 DDL：

CREATE TABLE IF NOT EXISTS `forum_forums` (
`forumID` int(11) NOT NULL AUTO_INCREMENT,
`forum_title` varchar(255) NOT NULL,
`forum_description` varchar(255) NOT NULL DEFAULT 'This forum does not have      a description',
`forum_total_threads` int(255) NOT NULL DEFAULT '0',
`forum_total_posts` int(255) NOT NULL DEFAULT '0',
`forum_latest_thread` varchar(255) NOT NULL DEFAULT 'There are no new   threads',
`forum_apart_of` int(11) NOT NULL,
`category_apart_of` int(11) NOT NULL,
 PRIMARY KEY (`forumID`)
 ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

CREATE TABLE IF NOT EXISTS `forum_categories` (
`catID` int(11) NOT NULL AUTO_INCREMENT,
`cat_title` varchar(255) NOT NULL,
PRIMARY KEY (`catID`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
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1 回答 1

1

您的问题： 我将如何在正确的类别 ID 中列出论坛？

解决方案： 由于您已经拥有数据库结构，并且您已经并且可能应该知道，为了将categories表与forums表链接起来，您需要在两个相似的列中至少有一个列，即category_id来自表的自动递增列，categories即id为了将您的论坛分类到特定类别中，您需要将该类别添加id到表格中的额外列中category_id，forums以便每个论坛都在 id 值中提到它的类别..！

然后您可以按以下方式列出您的论坛：

注意：此代码将检查每个论坛类别，并将列出每个类别下的所有论坛..！

<?php
//Assuming you have fetched whole data from forums table in $forums
//And whole data from categories in $categories
//So moving forward with the code

foreach ($categories  as $category) {
echo "<h1>".$category['category_title']."</h1>";
$category_id = $category['category_id'];
$query = mysqli_query($mysqli,"SELECT * FROM forums WHERE category_id='$category_id'");

$forums = array();
while ($rows = mysqli_fetch_array($query)) {
  $forums[] = $rows;
}

foreach ($forums as $forum) {
echo "Title :".$forum['forum_title']."</br>";
echo "Descripton :".$forum['forum_description']."</br></br></br>";
}
echo "</br></br></br></br>";  
} 
?>

工作代码示例：

<?php
$categories = array(
    array('id' => "04",'category_title' => "News & Support"),
    array('id' => "23",'category_title' => "Current Affairs"),
    array('id' => "12",'category_title' => "Politics"));

    $forums = array(
    array('forum_title' => "News 1",'category_id' => "04"),
    array('forum_title' => "News 2",'category_id' => "04"),
    array('forum_title' => "Current Afairs 1",'category_id' => "23"),
    array('forum_title' => "Current Afairs 2",'category_id' => "23"),
    array('forum_title' => "Politics 1",'category_id' => "12"),
    array('forum_title' => "Politics 2",'category_id' => "12")); 

foreach ($categories  as $category) {
echo "<h1>".$category['category_title']."</h1>";
$category_id = $category['id'];
$output = array();
for ($i=0;$i<=count($forums);$i++) {
if  ($category_id == $forums[$i]['category_id']) {
$add_forum = array('forum_title' => $forums[$i]['forum_title'],'category_id' => $forums[$i]['category_id']);
array_push($output, $add_forum);
}
}
for ($i=0;$i<=count($output);$i++) {
echo "Title :".$output[$i]['forum_title']."</br>";
}
echo "</br></br></br></br>";  
} 
?>

输出 ：

News & Support

Title :News 1
Title :News 2


Current Affairs

Title :Current Afairs 1
Title :Current Afairs 2


Politics

Title :Politics 1
Title :Politics 2
于 2016-05-05T21:10:36.967 回答