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使用 Spring.Net,可以查询某个(祖先)类型的所有对象。

        var ctx = ContextRegistry.GetContext();

        var setUsers = ctx.GetObjectsOfType(typeof(ISetUser)).Values.OfType<ISetUser>().ToList();

DryIoc 如何做到这一点?

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1 回答 1

1

给出示例类和接口的直接答案是:

public interface IA { }
public interface IB { }
public class AB : IA, IB { }
public class AA : IA { }

[Test]
public void Resolve_all_services_implementing_the_interface()
{
    var container = new Container();
    container.Register<IB, AB>();
    container.Register<AA>();

    // resolve IA's, even if no IA service type was registered
    var aas = container.GetServiceRegistrations()
        .Where(r => typeof(IA).IsAssignableFrom(r.Factory.ImplementationType ?? r.ServiceType))
        .Select(r => (IA)container.Resolve(r.ServiceType))
        .ToList();

    Assert.AreEqual(2, aas.Count);
}

如果您想检索某个接口,最好从一开始就注册它(为此做好计划):

[Test]
public void Resolve_automatically_registered_interface_services()
{
    var container = new Container();

    // changed to RegisterMany to automatically register implemented interfaces as services
    container.RegisterMany<AB>();
    container.RegisterMany<AA>();

    // simple resolve
    var aas = container.Resolve<IList<IA>>();

    Assert.AreEqual(2, aas.Count);
}
于 2016-05-06T10:16:42.547 回答