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我需要覆盖 QDataStream 的 >> 和 << 运算符。这是我的代码：

QDataStream &operator <<(QDataStream &out, const SScenarioEntry Entry)
{
    out.writeRawData(Entry.EntryName, sizeof(Entry.EntryName));
    out << Entry.Number;
    out << Entry.Type;
    out.writeRawData(Entry.RequestString, sizeof(Entry.RequestString));
    out.writeRawData(Entry.AnswerString, sizeof(Entry.AnswerString));
    out.writeRawData(Entry.AdditionalParams, sizeof(Entry.AdditionalParams));
    out << Entry.Timeout;
    return out;
}

QDataStream &operator >>(QDataStream &in, SScenarioEntry Entry)
{
    in.readRawData(Entry.EntryName, sizeof(Entry.EntryName));
    in >> Entry.Number;
    in >> Entry.Type;
    in.readRawData(Entry.RequestString, sizeof(Entry.RequestString));
    in.readRawData(Entry.AnswerString, sizeof(Entry.AnswerString));
    in.readRawData(Entry.AdditionalParams, sizeof(Entry.AdditionalParams));
    in >> Entry.Timeout;
    return in;
}

成功编译后，我得到一些像这样的误解：

first define here
In function `Z7qt_noopv':
multiple definition of `operator>>(QDataStream&, scnent)`

我有两个问题：

  1. 我必须如何定义 << 和 >> 运算符才能正确工作；
  2. 如果此代码正确，如何修复链接错误。


Tnx 寻求答案。

4

1 回答 1

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这很奇怪，但是通过划分功能公告和描述解决了问题。

于 2016-04-30T09:18:48.320 回答