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当我尝试在 Android 6 上请求权限时出现错误。

我的功能是：

// check ACCESS_FINE_LOCATION permission
var location2Permission = "android.permission.ACCESS_FINE_LOCATION";
var hasLocation2Permission = Ti.Android.hasPermission(location2Permission);

if(!hasLocation2Permission){
    permissionsToRequest.push(location2Permission);
}

// request permission
Ti.Android.requestPermissions(permissionsToRequest, function(e) {
    if (e.success) {
        Ti.API.info("SUCCESS");
        callback();
    } else {
        Ti.API.info("ERROR: " + e.error);
    }
});

错误是：

Message: Uncaught TypeError: Object #<Android> has no method 'requestPermissions'

发生了什么？因为在 Titanium Docs 中存在这个功能。我正在使用 Ti.SDK 5.1.2.GA

4

1 回答 1

1 
// The first argument is required on iOS and ignored on other platforms
var hasLocationPermissions = Ti.Geolocation.hasLocationPermissions(Ti.Geolocation.AUTHORIZATION_ALWAYS);
Ti.API.info('Ti.Geolocation.hasLocationPermissions', hasLocationPermissions);

if (hasLocationPermissions) {
    return alert('You already have permission.');
}

Ti.Geolocation.requestLocationPermissions(Ti.Geolocation.AUTHORIZATION_ALWAYS, function(e) {
    Ti.API.info('Ti.Geolocation.requestLocationPermissions', e);

    if (e.success) {

        // Instead, probably call the same method you call if hasLocationPermissions() is true
        alert('You granted permission.');

    } else if (OS_ANDROID) {
        alert('You denied permission for now, forever or the dialog did not show at all because it you denied forever before.');

    } else {

        // We already check AUTHORIZATION_DENIED earlier so we can be sure it was denied now and not before
        Ti.UI.createAlertDialog({
            title: 'You denied permission.',

            // We also end up here if the NSLocationAlwaysUsageDescription is missing from tiapp.xml in which case e.error will say so
            message: e.error
        }).show();
    }
});

有关更多信息，您可以查看链接以及文档

于 2016-04-26T15:16:43.943 回答