-2

我已经坐在这里几个小时试图弄清楚这一点。我还没有找到类似的问题（尽管我确信它已经完成了）。那么关于我的问题。当我编译它时，它很好。
我应该补充一点，unsortedList 是 Book*，它是一个结构。

string tit = tempBook->title;
string act = tempBook->action;
string aut = tempBook->author;
string sub = tempBook->subject;
char* tm = tempBook->time;

unsortedList[unsortedArrayLength].title;
unsortedList[unsortedArrayLength].action;
unsortedList[unsortedArrayLength].author;
unsortedList[unsortedArrayLength].subject;
unsortedList[unsortedArrayLength].time;

但是，当我编译它时，我收到一个错误：
Assign.exe 中的 0x5AC6516F (vcruntime140d.dll) 抛出异常：0xC0000005：访问冲突写入位置 0x00000000。 

string tit = tempBook->title;
string act = tempBook->action;
string aut = tempBook->author;
string sub = tempBook->subject;
char* tm = tempBook->time;

unsortedList[unsortedArrayLength].title = tit;
unsortedList[unsortedArrayLength].action = act;
unsortedList[unsortedArrayLength].author = aut;
unsortedList[unsortedArrayLength].subject = sub;
unsortedList[unsortedArrayLength].time = tm;

然后它会弹出 memcpy.asm 窗口，光标在这个位置： 

CopyUpByteLoop:
    mov     al, byte ptr [esi]
    mov     byte ptr [edi], al
    inc     esi
    inc     edi
    dec     ecx
    jne     CopyUpByteLoop

按要求定义 struct Book： 

    struct Book
{
    std::string title;
    std::string author;
    std::string subject;
    char* time;
    std::string action;
};

这是完整的功能：

    void DB::insertBook(Book* tempBook)
{
    using namespace std;
    unsortedArrayLength++;
    string tit = tempBook->title;
    string act = tempBook->action;
    string aut = tempBook->author;
    string sub = tempBook->subject;
    char* tm = tempBook->time;

    unsortedList[unsortedArrayLength].title = tit;
    unsortedList[unsortedArrayLength].action = act;
    unsortedList[unsortedArrayLength].author = aut;
    unsortedList[unsortedArrayLength].subject = sub;
    unsortedList[unsortedArrayLength].time = tm;

    system("cls");

    cout << "You have " << unsortedList[unsortedArrayLength].action <<":\n" << endl <<
    unsortedList[unsortedArrayLength].title << endl <<
    unsortedList[unsortedArrayLength].author << endl <<
    unsortedList[unsortedArrayLength].subject << endl <<
    "on " << unsortedList[unsortedArrayLength].time << endl << endl;

    printToLog(tempBook);
}

请帮助欧比旺。你是我唯一的希望...

4

1 回答 1

0

好吧，我想通了。我使数组的实例化更大。看来我达到了数组的上限。数组初始化为 2，我认为这已经足够了，但事实并非如此。:( 谢谢大家借给我他们的知识。

于 2016-04-24T02:25:45.730 回答