4

我正在尝试将 react-router-redux 与 redux-immutable 一起使用，并且在@@router/LOCATION_CHANGE触发操作时出现错误：

action @ 14:19:07.625 @@router/LOCATION_CHANGE 
%c prev state color: #9E9E9E; font-weight: bold Map { "repos": Map { "loading": false, "reposCount": 0 }, "users": Map { "loading": false, "usersCount": 0 }, "router": Map { "locationBeforeTransitions": null } }
%c action color: #03A9F4; font-weight: bold { type: '@@router/LOCATION_CHANGE',
  payload: 
   { pathname: 'blank',
     search: '',
     hash: '',
     state: null,
     action: 'POP',
     key: '5b05pd',
     query: {},
     '$searchBase': { search: '', searchBase: '' } } }
%c next state color: #4CAF50; font-weight: bold Map { "repos": Map { "loading": false, "reposCount": 0 }, "users": Map { "loading": false, "usersCount": 0 }, "router": Map { "locationBeforeTransitions": Map { "pathname": "blank", "search": "", "hash": "", "state": null, "action": "POP", "key": "5b05pd", "query": Map {}, "$searchBase": Map { "search": "", "searchBase": "" } } } }
—— log end ——
<Provider> does not support changing `store` on the fly. It is most likely that you see this error because you updated to Redux 2.x and React Redux 2.x which no longer hot reload reducers automatically. See https://github.com/reactjs/react-redux/releases/tag/v2.0.0 for the migration instructions.
Warning: [react-router] You cannot change <Router history>; it will be ignored

我一直在网上阅读这个问题似乎是由热加载程序引起的，但我没有使用它。

这是代码的样子：

路线

const routes = (
    <Route path="/" component={AppLayout}>
        <IndexRoute component={Home} />
        <Route path="/users" component={UsersPage} />
        <Route path="/repos" component={ReposPage} />
    </Route>
);

根组件

class Root extends React.Component<RootComponentProps, void> {
  public render() {
    const { store, history, routes } = this.props;
    return (
      <Provider store={store}>
        <div>
          <Router history={history}>
            {routes}
          </Router>
          <DevTools />
        </div>
      </Provider>
    );
  }
}

路由器减速器

const initialRouterReducerState = Immutable.fromJS({
    locationBeforeTransitions: null
});

let routerReducer = (state = initialRouterReducerState, action: any) => {
    if (action.type === LOCATION_CHANGE) {
        return state.merge({
            locationBeforeTransitions: action.payload
        });
    }
    return state;
};

主要的

// ...

let history = syncHistoryWithStore(browserHistory, store, {
    selectLocationState: (state: any) => state.get("routing").toJS()
});

render(
    <Root store={store} history={history} routes={routes} />,
    document.getElementById(container)
);

您对导致此问题的原因有任何想法吗？

4

2 回答 2

3

让我们在这里阅读错误：

<Provider> 不支持store即时更改。您很可能会看到此错误，因为您更新到 Redux 2.x 和 React Redux 2.x，它们不再自动热重载减速器。有关迁移说明，请参阅 https://github.com/reactjs/react-redux/releases/tag/v2.0.0。

在您的根组件中，您store从道具中获取，并且在每次路线更改时，它都会重新渲染所有内容。

https://github.com/reactjs/react-redux/blob/master/docs/api.md#react-router-10

Provider 应该呈现为顶级组件。路线将正确更改并传递道具，并且提供者将通过单个商店传递所有内容。

ReactDOM.render(
  <Provider store={store}>
    <Router history={history}>...</Router>
  </Provider>,
  targetEl
)

提供商应该在您的商店的顶部。你应该有许多不同的减速器。

于 2016-04-17T17:16:15.680 回答
-1

原来我所有的问题都是jsdom配置错误造成的。我创建了一个 dom.ts 文件，我可以从包含 mocha 单元测试的文件中导入该文件：

/// <reference path="../src/interfaces/interfaces.d.ts" />

let jsdom = require("jsdom");

// setup the simplest document possible
let doc = jsdom.jsdom(
    `<!doctype html>
    <html>
        <body>
            <div id="root"/><div>
        </body>
    </html>`,
    {
        url: "http://redux-bootstrap.com/"
    }
);

// get the window object out of the document
let win = doc.defaultView;

// set globals for mocha that make access to document and window feel 
// natural in the test environment
let g: any = global;
g.document = doc;
g.window = win;

// take all properties of the window object and also attach it to the 
// mocha global object
propagateToGlobal(win);

// from mocha-jsdom https://github.com/rstacruz/mocha-jsdom/blob/master/index.js#L80
function propagateToGlobal (window: any) {
  for (let key in window) {
    if (!window.hasOwnProperty(key)) { continue; }
    if (key in global) { continue; }
    g[key] = window[key];
  }
}
于 2016-04-18T00:51:02.953 回答