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我正在尝试从 C# 项目在 Meetup 上创建一个事件。我正在尝试使用此 API 方法。

我已经尝试了很多东西，现在我已经把它精简到尽可能简单。我的问题是，当我发送请求时，我收到错误请求，并显示“需要名称”的错误消息。我错过了什么？

这是相关的位：

var address = await GetAddressAsync(apiPath); 
// address is like: http://api.meetup.com/{groupID}/events?sign=true&key={API key}

var request = WebRequest.Create(address);
request.Method = "POST";
request.ContentType = "application/json";

var json = "{name: \"Tenshiko's Test Event\"}"; //JsonConvert.SerializeObject(requestObject);
using (var streamWriter = new StreamWriter(request.GetRequestStream()))
{
    streamWriter.Write(json);
}

try
{
    WebResponse response = await request.GetResponseAsync();

    var dataStream = response.GetResponseStream();
    StreamReader reader = new StreamReader(dataStream);
    string responseString = reader.ReadToEnd();

    var model = JsonConvert.DeserializeObject<TResponse>(responseString);

    reader.Close();
    dataStream.Close();
    response.Close();

    return model;
}
catch (WebException e)
{
    using (WebResponse response = e.Response)
    {
        HttpWebResponse httpResponse = (HttpWebResponse)response;

        using (Stream data = response.GetResponseStream())
        using (var reader = new StreamReader(data))
        {
            string text = reader.ReadToEnd();
        }
    }
}

编辑： 我尝试按照建议将“&name=something”添加到地址中，它可以工作......但是，问题还没有解决。该事件已创建，但其余数据（我以 json 格式发送）仍然无法通过。

4

1 回答 1

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似乎 StreamWriter 没有向您的 POST 请求添加任何数据，请尝试以下操作：

var address = await GetAddressAsync(apiPath); 
// address is like: http://api.meetup.com/{groupID}/events?sign=true&key={API key}

var json = "{name: \"Tenshiko's Test Event\"}"; 
var encoding = new ASCIIEncoding ();
var byte1 = encoding.GetBytes(json);

var request = WebRequest.Create(address);
request.Method = "POST";
request.ContentType = "application/json";
request.ContentLength = byte1.Length;

using (var reqstream = new request.GetRequestStream())
{
    reqstream.Write(byte1, 0, byte1.Length);
}

try
{
    WebResponse response = await request.GetResponseAsync();

    var dataStream = response.GetResponseStream();
    StreamReader reader = new StreamReader(dataStream);
    string responseString = reader.ReadToEnd();

    var model = JsonConvert.DeserializeObject<TResponse>(responseString);

    reader.Close();
    dataStream.Close();
    response.Close();

    return model;
}
catch (WebException e)
{
    using (WebResponse response = e.Response)
    {
        HttpWebResponse httpResponse = (HttpWebResponse)response;

        using (Stream data = response.GetResponseStream())
        using (var reader = new StreamReader(data))
        {
            string text = reader.ReadToEnd();
        }
    }
}
于 2016-04-15T20:10:14.370 回答