class MyClass
{
public:
~MyClass() {}
MyClass():x(0), y(0){} //default constructor
MyClass(int X, int Y):x(X), y(Y){} //user-defined constructor
MyClass(const MyClass& tempObj):x(tempObj.x), y(tempObj.y){} //copy constructor
private:
int x; int y;
};
int main()
{
MyClass MyObj(MyClass(1, 2)); //user-defined constructor was called.
MyClass MyObj2(MyObj); //copy constructor was called.
}
在第一种情况下,当MyClass(1, 2)
调用用户定义的构造函数并返回一个对象时,我期望MyObj
调用复制构造函数。为什么不需要为 的第二个实例调用复制构造函数MyClass
?