大家好,我有这个代码:
int lenInput;
char input[64], buffer[512], temp[512], *ret, tagName[] = "<name>", tagItem[] = "<item ";
bool deleted = false;
FILE *fp, *fpTemp = NULL;
if(! (fp = fopen(nameFile, "r+")) ) {
perror("Error Opening File");
exit(-1);
}
printf("Insert the Name of the service you want to erase... ");
fgets(input, sizeof(input), stdin);
lenInput = (int) strlen(input);
input[lenInput-1] = '\0';
lenInput = (int) strlen(input);
do {
fgets(buffer, sizeof(buffer), fp);
buffer[strlen(buffer)-1] = '\0';
if( (ret = strstr(buffer, tagName)) != NULL ) {
if( strncmp(ret, tagName, strlen(tagName)) == 0 ) {
if( (ret = strstr(ret, input)) != NULL ) {
if( strncmp(ret, input, lenInput) == 0 ) {
snprintf(temp, sizeof(temp), "<item present=\"false\">\n");
fputs(temp, fpTemp);
deleted = true;
}
}
}
}
else if( (ret = strstr(buffer, tagItem)) != NULL ) {
if( strncmp(ret, tagItem, strlen(tagItem)) == 0 ) {
fpTemp = fdopen( dup ( fileno(fp) ), "r+"); /* associates a stream with the existing file descriptor, fd */
}
}
} while( (deleted != true) && (!(feof(fp))) );
if(deleted == false)
printf("Error: Service Not Found!\n");
else
printf("Success: Service Erased!\n");
它适用于这样的文件:
<serviceNumber>2</serviceNumber>
<item present="true">
<id>1</id>
<name>name1</name>
<description>descr1</description>
<x>1</x>
<y>1</y>
</item>
<item present="true">
<id>2</id>
<name>name2</name>
<description>descr2</description>
<x>2</x>
<y>2</y>
</item>
主文件指针 ( FILE *fp
) 在main()
.
如果我找到标签,我的想法是复制文件指针fp
(在原型中传递),<item ...>
因为如果这个标签链接到我想要删除的服务的名称,我必须替换整个<item ...>
字符串.
但是,我有一个问题......当我执行snprintf()
andfputs()
时,文件在文件的开头被覆盖,因为,恕我直言,我认为文件指针不是重复的。
有办法或解决方法来修复/解决这个问题吗?
先感谢您!