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我正在将使用 SJCL 加密的数据接收到需要解密的 iOS 应用程序中。另一端是使用 SJCL 和 Apple 的CommonCrypto不支持的 AES CCM 模式，所以我为此使用VPCCMCrypt库。无法对发送 SJCL 密文的另一方进行任何更改。

以下是我的解密方法：

+ (NSData *)decryptSjcl:(NSDictionary *)cipher password:(NSString *)password {
    if (cipher == nil || password == nil) {
        return nil;
    }

    int version = [cipher[@"v"] intValue];
    NSString *iv = cipher[@"iv"];
    uint iter = [cipher[@"iter"] unsignedIntValue];
    uint ks = [cipher[@"ks"] unsignedIntValue];
    uint ts = [cipher[@"ts"] unsignedIntValue];
    NSString *mode = cipher[@"mode"];
    NSString *adata = cipher[@"adata"];
    NSString *algorithm = cipher[@"cipher"];
    NSString *salt = cipher[@"salt"];
    NSString *ct = cipher[@"ct"];

    if (version != 1 || ! [@"aes" isEqualToString:algorithm]) {
        return nil;
    }

    NSData *rawIv = [[NSData alloc] initWithBase64EncodedString:iv options:0];
    NSData *rawSalt = [[NSData alloc] initWithBase64EncodedString:salt options:0];
    NSData *rawAdata = [[NSData alloc] initWithBase64EncodedString:adata options:0];
    NSData *cipherData = [[NSData alloc] initWithBase64EncodedString:ct options:0];
    NSData *key;

    NSMutableData *decipheredData = nil;

    if ([@"ccm" isEqualToString:mode]) {
        key = [Cryptor sjclAesKeyForPassword:password salt:rawSalt iterations:iter keySize:ks];
        decipheredData = [Cryptor decryptAesCcmData:cipherData iv:rawIv key:key adata:rawAdata tagSize:ts];
    }

    return decipheredData;
}

SJCL 密钥生成：

+ (NSData *)sjclAesKeyForPassword:(NSString *)password salt:(NSData *)salt iterations:(uint)iterations keySize:(uint)keySizeBits {
    NSMutableData *derivedKey = [NSMutableData dataWithLength:keySizeBits / 8];

    int result = CCKeyDerivationPBKDF(kCCPBKDF2,
            password.UTF8String,
            [password lengthOfBytesUsingEncoding:NSUTF8StringEncoding],
            salt.bytes,
            salt.length,
            kCCPRFHmacAlgSHA256,
            iterations,
            derivedKey.mutableBytes,
            derivedKey.length);

    NSAssert(result == kCCSuccess, @"Unable to create AES key for password: %d", result);

    return derivedKey;
}

AES CCM 解密：

+ (NSMutableData *)decryptAesCcmData:(NSData *)cipherData iv:(NSData *)iv key:(NSData *)key adata:(NSData *)adata tagSize:(uint)tagSizeBits {
    VPCCMCrypt *ccm = [[VPCCMCrypt alloc] initWithKey:key
                                                   iv:iv
                                                adata:adata
                                            tagLength:tagSizeBits / 8];

    [ccm decryptDataWithData:cipherData
               finishedBlock:^(NSData *data) {
                   NSString *result = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

                   NSLog(@"Decrypted SJCL message: %@", result);
               }
                  errorBlock:^(NSError *error) {
                      NSLog(@"ERROR");
                  }];

    return nil;
}

来自 SJCL 的所有输入数据都被正确解析（IV、盐、密钥大小、标签大小、PBKDF 迭代、密文）并NSData从它们的Base64编码表示中解码。密码使用相同。包括创建的 AES 密钥在内的所有数据都不为零。

最后，它在验证 CCM 标签内失败VPCCMCrypt（标签不同）。上面的代码有问题吗？是否有任何其他 iOS/Objective-C/Swift 库来解密 AES CCM 甚至更好的 SJCL？我对 SJCL 库的 JavaScript 包装器不感兴趣。

为了进行测试，我使用了SJCL 演示页面中的简单加密数据。

编辑：

正如评论中所说，SJCL 发送 16 字节 IV 而不是 CCM 模式的最大 12 字节，然后在解密时将其内部钳制为最大 12 字节。这是更新的解密方法：

+ (NSData *)decryptSjcl:(NSDictionary *)cipher password:(NSString *)password {
    if (cipher == nil || password == nil) {
        return nil;
    }

    int version = [cipher[@"v"] intValue];
    NSString *iv = cipher[@"iv"];
    uint iter = [cipher[@"iter"] unsignedIntValue];
    uint ks = [cipher[@"ks"] unsignedIntValue];
    uint ts = [cipher[@"ts"] unsignedIntValue];
    NSString *mode = cipher[@"mode"];
    NSString *adata = cipher[@"adata"];
    NSString *algorithm = cipher[@"cipher"];
    NSString *salt = cipher[@"salt"];
    NSString *ct = cipher[@"ct"];

    if (version != 1 || ! [@"aes" isEqualToString:algorithm]) {
        return nil;
    }

    NSMutableData *rawIv = [[NSMutableData alloc] initWithBase64EncodedString:iv options:0];
    NSMutableData *rawSalt = [[NSMutableData alloc] initWithBase64EncodedString:salt options:0];
    NSMutableData *rawAdata = [[NSMutableData alloc] initWithBase64EncodedString:adata options:0];
    NSMutableData *cipherData = [[NSMutableData alloc] initWithBase64EncodedString:ct options:0];
    NSData *key;

    NSData *decipheredData = nil;

    if ([@"ccm" isEqualToString:mode]) {
        key = [Cryptor sjclAesKeyForPassword:password salt:rawSalt iterations:iter keySize:ks];

        // Clamp the SJCL IV - They use a 16 byte IV for CCM mode which is against specification and they do a funky
        // clamping. CCM mode IV should be max 13 bytes long. They almost always clamp it to 13 bytes but save the whole
        // 16 bytes in their JSON container.
        // for (L=2; L<4 && ol >>> 8*L; L++) {}
        // if (L < 15 - ivl) { L = 15-ivl; }
        // iv = w.clamp(iv,8*(15-L));
        int64_t ivl = rawIv.length;
        int64_t ol = cipherData.length - (ts / 8);
        int64_t L = 2;
        for (L = 2; L < 4 && ol >> 8*L; L++) {}
        if (L < 15 - ivl) {
            L = 15 - ivl;
        }
        NSRange subrange = NSMakeRange(0, (NSUInteger)(15 - L));

        decipheredData = [Cryptor decryptAesCcmData:cipherData iv:[rawIv subdataWithRange:subrange] key:key adata:rawAdata tagSize:ts];
    }
    else {
        decipheredData = nil;
    }

    return decipheredData;
}

最后缺少的一件事是验证 TAG，我无法做到这一点。有任何想法吗？

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1 回答 1

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SJCL 在 AES-CCM 模式下不使用整个 (128/192/256bit) IV，但演示页面显示了它。尝试使用更少的字节。

在这里您可以找到 IV 长度计算的工作原理： http ://bitwiseshiftleft.github.io/sjcl/doc/symbols/src/core_ccm.js.html

for (L=2; L<4 && ol >>> 8*L; L++) {}
if (L < 15 - ivl) { L = 15-ivl; }
iv = w.clamp(iv,8*(15-L));
于 2016-04-20T14:14:09.373 回答