3

我有一个线程对象数组,每个线程对象都有属性

unit:number
task:number
subtask:number

我想创建一个管道来过滤这些线程,到目前为止我有一个如下所示的工作管道。我对它还不是很满意,想问你们是否有更优雅的解决方案?

HTML:

<div class="thread-item" *ngFor="#thread of threadlist | threadPipe:unitPipe:taskPipe:subtaskPipe"></div>

管道.ts

export class ThreadPipe implements PipeTransform{

  threadlistCopy:Thread[]=[];

  transform(array:Thread[], [unit,task,subtask]):any{

    //See all Threads
    if(unit == 0 && task == 0 && subtask == 0){
      return array
    }
    //See selected Units only
    if(unit != 0 && task == 0 && subtask == 0){
      this.threadlistCopy=[];
      for (var i = 0; i<array.length;i++){
        if(array[i].unit == unit){
          this.threadlistCopy.push(array[i])
        }
      }
      return this.threadlistCopy
    }
    //See selected Units and Tasks
    if (unit != 0 && task != 0 && subtask == 0){
      this.threadlistCopy=[];
      for (var i = 0; i<array.length;i++){
        if(array[i].unit == unit && array[i].task == task){
          this.threadlistCopy.push(array[i])
        }
      }
      return this.threadlistCopy
    }
    // See selected units, tasks, subtask
    if (unit != 0 && task != 0 && subtask != 0){
      this.threadlistCopy=[];
      for (var i = 0; i<array.length;i++){
        if(array[i].unit == unit && array[i].task == task && array[i].subtask == subtask){
          this.threadlistCopy.push(array[i])
        }
      }
      return this.threadlistCopy
    }
  }
}
4

1 回答 1

6

您正在以正确的方式实现管道,但您基本上是在重新发明Array.prototype.filter代码中的机制。一个更简单的方法是:

export class ThreadPipe implements PipeTransform{

  transform(array:Thread[], [unit,task,subtask]):any{

    //See all Threads
    if(unit == 0 && task == 0 && subtask == 0){
      return array
    }
    //See selected Units only
    if(unit != 0 && task == 0 && subtask == 0){
      return array.filter(thread => {
        return thread.unit === unit;
      });
    }
    //See selected Units and Tasks
    if (unit != 0 && task != 0 && subtask == 0){
      return array.filter(thread => {
        return thread.unit === unit && thread.task === task;
      });
    }
    // See selected units, tasks, subtask
    if (unit != 0 && task != 0 && subtask != 0){
      return array.filter(thread => {
        return thread.unit === unit && thread.task === task && thread.subtask === subtask;
      });
    }
  }
}
于 2016-04-05T11:56:40.997 回答