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我使用 Swagger Editor 手动生成我的 Swagger 规范文件并为 Python Flask 服务器生成文件。按照自述文件我安装了 connexion，但是当我运行时python app.py出现错误：ValueError: need more than 1 value to unpack。有任何想法吗？

下面的完整堆栈跟踪：

No handlers could be found for logger "connexion.api"
Traceback (most recent call last):
  File "app.py", line 5, in <module>
    app.add_api('swagger.yaml')
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/app.py", line 144, in add_api
    debug=self.debug)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 127, in __init__
    self.add_paths()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 198, in add_paths
    six.reraise(*sys.exc_info())
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 187, in add_paths
    self.add_operation(method, path, endpoint, path_parameters)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 160, in add_operation
    resolver=self.resolver)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/operation.py", line 168, in __init__
    resolution = resolver.resolve(self)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/resolver.py", line 50, in resolve
    return Resolution(self.resolve_function_from_operation_id(operation_id), operation_id)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/resolver.py", line 71, in resolve_function_from_operation_id
    return self.function_resolver(operation_id)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/utils.py", line 106, in get_function_from_name
    module_name, attr_path1 = module_name.rsplit('.', 1)
ValueError: need more than 1 value to unpack
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1 回答 1

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我也遇到了这个。据我所知，Swagger 生成的代码似乎假设您使用的是 Python 3。虽然 connexion 支持 Python 2.7 和 3.4+，但它确实需要__init__.py在生成的python-flask-server/基本目录以及controllers/子目录中的文件才能为 Python 工作2.7（隐式命名空间包是在 Python 3.3 中引入的）。如果您在生成代码后创建这 2 个空文件，则一切正常。如果 Swagger 生成器想要支持 Python 2.7（因为 connexion 允许它），它也只需要提供这些文件。

于 2016-04-07T00:56:06.650 回答