5

Python

我从 Wunderground 获得了 122 天的天气数据，这些数据没有相等的时间采样间隔。这是我的数据示例：

Bangor Weather Data from Wunderground
Datetime,Temp(F),Precip(in.),Snow (in.),PET(in./day),Baro(mBar)
    2015-12-02 01:30:00,1.1,0.3,0.0,0.45524647117649564,1017.5 
    2015-12-02 01:53:00,1.1,0.3,0.0,0.45524647117649564,1017.6 
    2015-12-02 02:20:00,1.1,0.3,0.0,0.45524647117649564,1017.2 
    2015-12-02 02:53:00,1.7,0.5,0.0,0.500024812603692,1016.7 
    2015-12-02 02:55:00,1.7,0.3,0.0,0.500024812603692,1016.5 
    2015-12-02 03:09:00,1.1,0.3,0.0,0.45524647117649564,1016.1 
    2015-12-02 03:33:00,1.1,0.5,0.0,0.45524647117649564,1016.1 
    2015-12-02 03:53:00,1.7,0.8,0.0,0.500024812603692,1016.1 
    2015-12-02 04:34:00,1.7,0.5,0.0,0.500024812603692,1015.1 
    2015-12-02 04:46:00,1.7,0.5,0.0,0.500024812603692,1015.1 
    2015-12-02 04:53:00,1.7,0.8,0.0,0.500024812603692,1015.1 
    2015-12-02 05:13:00,1.7,0.0,0.0,0.500024812603692,1014.4

我想为我的整个数据集获取每日降雪量（新的一天重置为零）。我希望我的输出看起来像：

    2015-12-01,0.0
    2015-12-02,0.0
    2015-12-03,1.0
    2015-12-04,3.0
    2015-12-05,0.0
    2015-12-06,1.0

我怎样才能使用熊猫来做到这一点？

4

2 回答 2

2

那是你要的吗？

df.groupby(df.Datetime.dt.date)['Snow (in.)'].sum()

这将为您提供每天的降雪量（总和）

于 2016-04-03T18:03:59.587 回答
0

您还可以使用：

df['Snow (in.)'].resample('D').sum()
于 2017-10-08T21:53:00.023 回答