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So I have login form, when user click login I will check the inputs.

First what I do, onlick of login button i call textinputlayout.seterrorenabled(false), then when API call is over and I have an error on my editttext i call textinputlayout.seterrorenabled(true), textinputlayout.seterror(message). Everything is all good, now I click on login again and repeat same process textinputlayout.seterrorenabled(false) and then after API call is over textinputlayout.seterrorenabled(true), textinputlayout.seterror(message). However this time the message doesn't show up. What's the problem?

          <android.support.design.widget.TextInputLayout
                android:id="@+id/usernameField1"
                android:layout_width="match_parent"
                android:layout_height="wrap_content">
                <EditText
                    android:id="@+id/usernameField"
                    android:layout_width="match_parent"
                    android:layout_height="wrap_content"
                    android:hint="@string/user_name"
                    android:textColorHint="#808080"
                    android:paddingBottom="@dimen/tendp"
                    android:paddingLeft="@dimen/tendp"
                    android:paddingRight="@dimen/tendp"
                    android:paddingTop="@dimen/tendp"
                    android:textSize="@dimen/textSize" />
            </android.support.design.widget.TextInputLayout>
            <android.support.design.widget.TextInputLayout
                android:id="@+id/passwordField1"
                android:layout_width="match_parent"
                android:layout_height="wrap_content">
                <EditText
                    android:id="@+id/passwordField"
                    android:layout_width="match_parent"
                    android:layout_height="wrap_content"
                    android:hint="@string/password"
                    android:textColorHint="#808080"
                    android:paddingBottom="@dimen/tendp"
                    android:inputType="textPassword"
                    android:paddingLeft="@dimen/tendp"
                    android:paddingRight="@dimen/tendp"
                    android:paddingTop="@dimen/tendp"
                    android:textSize="@dimen/textSize" />
            </android.support.design.widget.TextInputLayout>
                <Button
                    android:id="@+id/login"
                    android:layout_width="match_parent"
                    android:layout_height="wrap_content"
                    android:layout_gravity="center"
                    android:gravity="center"
                    android:background="?attr/selectableItemBackground"
                    android:text="@string/login"
                    android:visibility="gone"
                    android:textColor="@android:color/white"
                    android:textSize="@dimen/textSize" >
                </Button>



  final Button login =  (Button) findViewById(R.id.login);
    //  login.setOnClickListener(new OnClickListener() {

        login.setOnClickListener(here i set my textinputlayout to errorenabled false or seterror null // start an asynctask 



  here in asynctask onpostexecute i set the errorenabled(true) and set error( the message)
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1 回答 1

-1

请勿使用textinputlayout.seterrorenabled(true)textinputlayout.seterrorenabled(true)textinputlayout.seterror(message)在您想显示消息或textinputlayout.seterror(null)不使用时

于 2016-03-26T10:01:15.653 回答