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我正在编写一个使用 BGL 对图形执行一些计算的函数。计算的方式取决于图是否有向，但我想避免编写两个不同的函数，一个用于无向图，一个用于有向图。两种类型的图定义如下

using namespace boost;
// Undirected
typedef adjacency_list<listS, vecS, undirectedS> UGraph;
// Directed
typedef adjacency_list<listS, vecS, bidirectionalS> DGraph;

有没有办法检查图形是否从图形对象本身定向？换句话说，有没有办法从图形对象中知道所使用的“有向性”属性（即，无向S、双向S 或有向S）？

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1 回答 1

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print_graph()我在查看graph_utility.hpp中的函数定义时找到了答案，这使我找到了graph_traits.hppis_directed()中定义的函数。

我想可能有一种更优雅的方式来做到这一点，但这是一个最小的工作示例：

#include <iostream>
#include <boost/graph/adjacency_list.hpp>
#include <boost/graph/graph_traits.hpp>


template <typename graph_t>
void print_directedness(graph_t &g)
{
  // Typedef of an object whose constructor returns "directedness" of the graph object.
  typedef typename boost::graph_traits<graph_t>::directed_category Cat;
  // The function boost::detail::is_directed() returns "true" if the graph object is directed.
  if(boost::detail::is_directed(Cat()))
    std::cout << "The graph is directed." << std::endl;
  else
    std::cout << "The graph is undirected." << std::endl;
}


int main()
{

  // Creates an undirected graph and tests whether it is directed of not.
  boost::adjacency_list< boost::setS, boost::vecS, boost::undirectedS > UnGraph;
  print_directedness(UnGraph);

  // Creates a directed graph and tests whether it is directed of not.
  boost::adjacency_list< boost::setS, boost::vecS, boost::directedS > DiGraph;
  print_directedness(DiGraph);

  // Creates a bidirectional graph and tests whether it is directed of not.
  boost::adjacency_list< boost::setS, boost::vecS, boost::bidirectionalS > BidiGraph;
  print_directedness(BidiGraph);

  return 0;
}

正确返回

>> g++ minimal_working_example.cpp -o minimal_working_example
>> ./minimal_working_example
The graph is undirected.
The graph is directed.
The graph is directed.
于 2016-05-17T16:34:57.870 回答