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我尝试使用 Liquidsoap 和 gstream 将我的频道重新传输到另一个频道。我想这样做是因为后备，如果第一个不使用，则使用另一个来源。我有：

set("frame.video.width", 1920)
set("frame.video.height", 1080)
#set("frame.video.samplerate", 30)
set("gstreamer.add_borders", false)
set("clock.allow_streaming_errors",false)

s = single("rtmp://link_to_rtmp_stream/test")
s = fallback([s, blank()])

output.gstreamer.audio_video(
  video_pipeline=
    "videoconvert ! x264enc bitrate=4000 ! video/x-h264,profile=baseline ! queue ! mux.",
  audio_pipeline=
    "audioconvert ! voaacenc bitrate=128000 ! queue ! mux.",
  pipeline=
    "flvmux name=mux ! rtmpsink location=\"rtmp://wherewewhantstream.com live=1\"",
  s)

我遇到了一个问题..识别第一个流..脚本不想识别它，因为它认为它是文件。如何识别rtmp流并解码？

4

1 回答 1

2

尝试这个：

set("frame.video.width", 1920)
set("frame.video.height", 1080)
#set("frame.video.samplerate", 30)
set("gstreamer.add_borders", false)
set("clock.allow_streaming_errors",false)

def gstreamer.rtmp(~id="",uri) =
  pipeline = "rtmpsrc location=#{uri} ! tee name=t"
  audio_pipeline = "t. ! queue"
  video_pipeline = "t. ! queue"
  input.gstreamer.audio_video(id=id, pipeline=pipeline, audio_pipeline=audio_pipeline, video_pipeline=video_pipeline)
end

s = gstreamer.rtmp("rtmp://link_to_rtmp_stream/test")
s = fallback([s, blank()])

output.gstreamer.audio_video(
  video_pipeline=
    "videoconvert ! x264enc bitrate=4000 ! video/x-h264,profile=baseline ! queue ! mux.",
  audio_pipeline=
    "audioconvert ! voaacenc bitrate=128000 ! queue ! mux.",
  pipeline=
    "flvmux name=mux ! rtmpsink location=\"rtmp://wherewewhantstream.com live=1\"",
  s)
于 2016-06-09T22:53:34.570 回答