我有这个输入文本:
<html><head><meta http-equiv="content-type" content="text/html; charset=utf-8"></head><body><table cellspacing="0" cellpadding="0" border="0" align="center" width="603">   <tbody><tr>     <td><table cellspacing="0" cellpadding="0" border="0" width="603">       <tbody><tr>         <td width="314"><img height="61" width="330" src="/Elearning_Platform/dp_templates/dp-template-images/awards-title.jpg" alt="" /></td>         <td width="273"><img height="61" width="273" src="/Elearning_Platform/dp_templates/dp-template-images/awards.jpg" alt="" /></td>       </tr>     </tbody></table></td>   </tr>   <tr>     <td><table cellspacing="0" cellpadding="0" border="0" align="center" width="603">       <tbody><tr>         <td colspan="3"><img height="45" width="603" src="/Elearning_Platform/dp_templates/dp-template-images/top-bar.gif" alt="" /></td>       </tr>       <tr>         <td background="/Elearning_Platform/dp_templates/dp-template-images/left-bar-bg.gif" width="12"><img height="1" width="12" src="/Elearning_Platform/dp_templates/dp-template-images/left-bar-bg.gif" alt="" /></td>         <td width="580"><p> what y all heard?</p><p>i'm shark oysters.</p>             <p> </p>             <p> </p>             <p> </p>             <p> </p>             <p> </p>             <p> </p></td>         <td background="/Elearning_Platform/dp_templates/dp-template-images/right-bar-bg.gif" width="11"><img height="1" width="11" src="/Elearning_Platform/dp_templates/dp-template-images/right-bar-bg.gif" alt="" /></td>       </tr>       <tr>         <td colspan="3"><img height="31" width="603" src="/Elearning_Platform/dp_templates/dp-template-images/bottom-bar.gif" alt="" /></td>       </tr>     </tbody></table></td>   </tr> </tbody></table> <p> </p></body></html>
如您所见,这段 HTML 文本中没有换行符,我需要查找其中的所有图像链接,将它们复制到目录中,然后将文本中的行更改为./images/file_name.
目前,我使用的 Perl 代码如下所示:
my ($old_src,$new_src,$folder_name);
    foreach my $record (@readfile) {
        ## so the if else case for the url replacement block below will be correct
        $old_src = "";
        $new_src = "";
        if ($record =~ /\<img(.+)/){
            if($1=~/src=\"((\w|_|\\|-|\/|\.|:)+)\"/){
                $old_src = $1;
                my @tmp = split(/\/Elearning/,$old_src);
                $new_src = "/media/www/vprimary/Elearning".$tmp[-1];
                push (@images, $new_src);
                $folder_name = "images";
            }## end if
        }
        elsif($record =~ /background=\"(.+\.jpg)/){
            $old_src = $1;
            my @tmp = split(/\/Elearning/,$old_src);
            $new_src = "/media/www/vprimary/Elearning".$tmp[-1];
            push (@images, $new_src);
            $folder_name = "images";
        }
        elsif($record=~/\<iframe(.+)/){
            if($1=~/src=\"((\w|_|\\|\?|=|-|\/|\.|:)+)\"/){
                $old_src = $1;
                my @tmp = split(/\/Elearning/,$old_src);
                $new_src = "/media/www/vprimary/Elearning".$tmp[-1];
                ## remove the ?rand behind the html file name
                if($new_src=~/\?rand/){
                    my ($fname,$rand) = split(/\?/,$new_src);
                    $new_src = $fname;
                    my ($fname,$rand) = split(/\?/,$old_src);
                    $old_src = $fname."\\?".$rand;
                }
        print "old_src::$old_src\n"; ##s7test
        print "new_src::$new_src\n\n"; ##s7test
                push (@iframes, $new_src);
                $folder_name = "iframes";
            }## end if
        }## end if
        my $new_record = $record;
        if($old_src && $new_src){
            $new_record =~ s/$old_src/$new_src/ ;
    print "new_record:$new_record\n"; ##s7test
            my @tmp = split(/\//,$new_src);
            $new_record =~ s/$new_src/\.\\$folder_name\\$tmp[-1]/;
##  print "new_record2:$new_record\n\n"; ##s7test
        }## end if
        print WRITEFILE $new_record;
    } # foreach
这仅足以处理其中包含换行符的 HTML 文本。我以为只循环正则表达式语句,但随后我必须将匹配行更改为其他文本。
您是否知道是否有一种优雅的 Perl 方法可以做到这一点?或者,也许我太笨了,看不到明显的做法,而且我知道把全局选项放在一边是行不通的。
谢谢。〜史蒂夫