0

我对以下方法有困难。我不知道我的问题是否存在，但我已将其范围缩小到不从文件中填充数组列表。任何帮助是极大的赞赏。

private void searchButtonActionPerformed(java.awt.event.ActionEvent evt) {

//create arraylists
ArrayList<String> model = new ArrayList<String>();
ArrayList<String> length = new ArrayList<String>();
ArrayList<String> width = new ArrayList<String>();
ArrayList<String> radius = new ArrayList<String>();
ArrayList<String> depth = new ArrayList<String>();
ArrayList<String> volume = new ArrayList<String>();
ArrayList<String> shape = new ArrayList<String>();

//fill arraylists from file
try {
    String outputline = "";

    BufferedReader fin = new BufferedReader(new FileReader("stock.dat"));
    while((outputline = fin.readLine()) != null)    {
       // for(int i = 0; i < outputline.length(); i++)    {
       int i = 0;

            //model
            boolean flag = false;
            String pass = "";
            while(flag = false) {
                if(outputline.charAt(i) != ',')
                    pass.concat(Character.toString(outputline.charAt(i)));

                else
                    flag = true;
                i++;
            }
            model.add(pass);

            //length
            flag = false;
            pass = "";
            while(flag = false) {
                if(outputline.charAt(i) != ',') 
                    pass.concat(Character.toString(outputline.charAt(i)));
                else
                    flag = true;
            }
            length.add(pass);

            //width
            flag = false;
            pass = "";
            while(flag = false) {
                if(outputline.charAt(i) != ',') 
                    pass.concat(Character.toString(outputline.charAt(i)));
                else
                    flag = true;
            }
            width.add(pass);

            //radius
            flag = false;
            pass = "";
            while(flag = false) {
                if(outputline.charAt(i) != ',') 
                    pass.concat(Character.toString(outputline.charAt(i)));
                else
                    flag = true;
            }
            radius.add(pass);

            //depth
            flag = false;
            pass = "";
            while(flag = false) {
                if(outputline.charAt(i) != ',') 
                    pass.concat(Character.toString(outputline.charAt(i)));
                else
                    flag = true;
            }
            depth.add(pass);

            //volume
            flag = false;
            pass = "";
            while(flag = false) {
                if(outputline.charAt(i) != ',') 
                    pass.concat(Character.toString(outputline.charAt(i)));
                else
                    flag = true;
            }
            volume.add(pass);

            //shape
            pass = "";
            for(int j = i; j < outputline.length(); j++)
                pass.concat(Character.toString(outputline.charAt(i)));
            shape.add(pass);
        }
    fin.close();
    }
catch(IOException e)    {
    System.err.print("Unable to read from file");
    System.exit(-1);

}

int at = -1;
for(int i = 0; i < model.size(); i++)   {
    if(model.get(i).equals(searchIn.getText())) {
        at = i;
        i = model.size();
    }
}
    Component frame = null;

if(at != -1)    {
    searchDepthOut.setText(depth.get(at));
    searchLengthOut.setText(length.get(at));
    searchRadiusOut.setText(radius.get(at));
    searchVolumeOut.setText(volume.get(at));
    searchWidthOut.setText(width.get(at));

}
else
    JOptionPane.showMessageDialog(null, "Your search did not return any results", "ERORR", JOptionPane.ERROR_MESSAGE);

}

4

4 回答 4

4

用逗号分隔 readline 并完成它。我还将为模型、长度、宽度等创建一个对象......然后拥有该对象的 1 个数组列表。

while((outputline = fin.readLine()) != null)    {

    String[] tokens = outputline.split(",");
    if(tokens.length == 7){
        SObj o = new SObj; //Some Object

        o.model = tokens[0];
        o.length = tokens[1];
        //and so on

        oList.add(o);
    }
}
于 2008-12-12T03:10:23.267 回答
3

除了人们列出的所有其他问题......

String pass = "";
while(flag = false) {
if(outputline.charAt(i) != ',')
   pass.concat(Character.toString(outputline.charAt(i)));

pass 是一个字符串。字符串是不可变的。你要

   pass = pass.concat(.....)
于 2008-12-12T03:06:02.573 回答
2

while(flag = false)永远不会运行 - 它总是评估为false. 尝试while (!flag)

于 2008-12-12T03:10:36.590 回答
0

我建议你重构代码。问题不仅在于存在某种解析器错误，而且很难判断发生了什么 - 代码显然对输入行的结构做出了假设，但您必须通读并跟踪在你的脑海中重构它的方法。

就像是

/** Expect a line of the form model, length, ...,
  return a list of ... 
*/
private String[] parse (String inputLine)
{
  //check input line charachteristics-not null, length, ...
  String out=  inputLine.split(",");
  if (out.length()!= ... 
  //whatever sanity checking...

}

private List<String[]> extract(BufferedReader fin)
{
  while((outputline = fin.readLine()) != null) 
 {
    //do something with parse(outputline);
  }
}

有用的是将文件读取和行解析分开，这样您就可以看到发生了什么问题，而不是按顺序进行所有操作，这很可能是对隐藏在代码中的行结构的假设。它需要 4 个逗号分隔的整数吗？5? 如果他们用空格填充呢？以空行为前缀？

于 2008-12-12T03:15:13.770 回答