我正在使用 PHP 和 MySQL (PHPMyAdmin) 制作注册表单，当我在浏览器 (Mozilla Firefox) 上打开页面时，我得到
解析错误：语法错误，第 71 行中的意外 $end
<?php
require('config.php');
if(isset($_POST['submit'])){
//Verificació
$email1 = $_POST['email1'];
$email2 = $_POST['email2'];
$pass1 = $_POST['pass1'];
$pass2 = $_POST['pass2'];
if($email1 == $email2){
if ($pass1 == $pass2){
//Tot bé!
$name = mysql_escape_string($_POST['name']);
$lname = mysql_escape_string($_POST['lname']);
$email1 = mysql_escape_string($email1);
$email2 = mysql_escape_string($email2);
$pass1 = mysql_escape_string($pass1);
$pass2 = mysql_escape_string($pass2);
}else{
die("Sorry, your passwords didn't match");
}
}else{
die("Sorry, your emails didn't match");
}
}else{
echo <<<EOD
<form action='register.php' method='POST'>
First name:<input type='text' name='name' /><br/>
Last name:<input type='text' name='lName' /><br/>
Username:<input type='text' name='username' /><br/>
Email:<input type='text' name='email' /><br/>
Password:<input type='password' name='pass1' /><br/>
Confirm password:<input type='password' name='pass2' /><br/>
<input type='submit' value='Register' name='submit' />
</form>
EOD;
}
?>
我在做什么坏事？有人能帮助我吗？