4

I am using ContactsContract api intent for showing all contacts from an activity. This intent returns an id of the contact. I need to get the postal address of this contact.

Here is the code which i am using for showing contacts:

Intent intent = new Intent(Intent.ACTION_PICK); intent.setType(ContactsContract.Contacts.CONTENT_TYPE); startActivityForResult(intent, PICK_CONTACT);

I am getting the result in the onActivityResult function.

Please help, how do i do this.

4

4 回答 4

10

在您的 onActivityResult 中，首先获取联系人 ID 并查询 ContactsContract.Data 以获取相关数据：

// get the contact ID

Cursor cursor = getContentResolver().query(data.getData(), null, null, null, null);
cursor.moveToFirst();
long id = cursor.getLong(cursor.getColumnIndex(ContactsContract.Contacts._ID));
cursor.close();

// get the data package containg the postal information for the contact
cursor = getContentResolver().query(ContactsContract.Data.CONTENT_URI, 
    new String[]{ StructuredPostal.STREET,
        StructuredPostal.CITY,
// add more coluns from StructuredPostal if you need them
        StructuredPostal.POSTCODE},
        ContactsContract.Data.CONTACT_ID + "=? AND " +
            StructuredPostal.MIMETYPE + "=?",
        new String[]{String.valueOf(id), StructuredPostal.CONTENT_ITEM_TYPE},
        null);


Street = cursor.getString(cursor.getColumnIndex(StructuredPostal.STREET));
Postcode = cursor.getString(cursor.getColumnIndex(StructuredPostal.POSTCODE));
City = cursor.getString(cursor.getColumnIndex(StructuredPostal.CITY)));
// etc.
于 2010-08-31T16:24:49.550 回答
2

也可以这样做（代码较少）

以这种方式发送意图：

Intent intent = new Intent(Intent.ACTION_PICK);

intent.setType(ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_TYPE); startActivityForResult(intent, PICK_CONTACT);

在 onActivityResult 方法中

Uri contactData = data.getData();
Cursor c =  managedQuery(contactData, null, null, null, null);
if (c.moveToFirst()) {
    String address = c.getString(c.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.StructuredPostal.FORMATTED_ADDRESS));
}
于 2010-10-23T12:36:34.133 回答
1

这将返回联系人邮政地址中的所有地址。

     Uri uri = ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_URI;
     String sortOrder = StructuredPostal.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
      Cursor cr = getContentResolver().query(uri,null, null, null, sortOrder);
      while(cr.moveToNext())
{
    String  Street = cr.getString(cr.getColumnIndex(StructuredPostal.STREET));
    String  Postcode = cr.getString(cr.getColumnIndex(StructuredPostal.POSTCODE));
    String  City = cr.getString(cr.getColumnIndex(StructuredPostal.CITY));
    Toast.makeText(this,"Address is : " +City+","+Street ,Toast.LENGTH_SHORT).show();
      }
      cr.close();
于 2012-10-13T21:58:08.700 回答
1

Kiran 的答案可能适用于 Android 2.0 及更高版本，但当您希望它与 Android 1.6 及更低版本兼容时，您需要稍微调整代码：

Intent intent = new Intent(Intent.ACTION_PICK);
intent.setType(Contacts.ContactMethods.CONTENT_POSTAL_TYPE);
startActivityForResult(intent, PICK_CONTACT);

在 onActivtyResult 方法中：

Uri contactData = data.getData();
Cursor c =  managedQuery(contactData, null, null, null, null);
if (c.moveToFirst()) {
   String address = c.getString(c.getColumnIndexOrThrow(Contacts.ContactMethodsColumns.DATA));
}

哪里PICK_CONTACT是int你自己的选择。（正确的？）

于 2011-02-10T15:53:09.467 回答