我有一个用于传递 SOAP 命令的通用函数。我需要查看发送到服务器的 RAW XML 数据以诊断错误。我怎么做?
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21516 次
2 回答
18
没关系,这似乎非常接近点!
http://www.scottnichol.com/nusoapintro.htm
echo '<h2>Request</h2>';
echo '<pre>' . htmlspecialchars($client->request, ENT_QUOTES) . '</pre>';
echo '<h2>Response</h2>';
echo '<pre>' . htmlspecialchars($client->response, ENT_QUOTES) . '</pre>';
// Display the debug messages
echo '<h2>Debug</h2>';
echo '<pre>' . htmlspecialchars($client->debug_str, ENT_QUOTES) . '</pre>';
于 2010-08-31T06:09:19.680 回答
1
虽然这是一篇旧帖子,但我想用我自己的 tzmatt 答案来补充一下。
class soapBug {
/*
* @var obj $debug client object
* @var string $what Just a name for the header so you know
* what you are looking at.
*/
public function bug($debug, $what) {
/* ive stayed with the original here, but you could look at
* http://www.php.net/manual/en/tidy.repairstring.php to
* output in clean xml.
*
* I just grab the line i need and paste
* it into my IDE and let it format for me, works just as well
* and no coding to fiddle with for something that wont be
* permanent on my project.
*/
echo '<h2>' . $what . '</h2>';
echo '<pre>' . htmlspecialchars($debug, ENT_QUOTES) . '</pre>';
}
}
class someClass {
private $de;
// private to this class to prevent accidental call
// outside the class.
public function __construct() {
$this->de = new soapBug;
}
public function thatNeedsDebugging() {
/*
* Simple enough to debug your client now no need to copy
* the html block all over you can debug with just one line
* of call all of them
*/
$this->de->bug($client->request, 'Request'); // I grab this output string
$this->de->bug($client->response, 'Response');
$this->de->bug($client->debug_str, 'Debug');
}
}
于 2016-06-15T22:51:00.037 回答