18

我已经开始使用 Locust 进行性能测试。我想向两个不同的端点发出两个发布请求。但是第二个 post 请求需要第一个请求的响应。如何以方便的方式做到这一点。我已经尝试过如下但不工作。

from locust import HttpLocust, TaskSet, task

class GetDeliveryDateTasks(TaskSet):

    request_list = []

    @task
    def get_estimated_delivery_date(self):
        self.client.headers['Content-Type'] = "application/json"
        response = self.client.post("/api/v1/estimated-delivery-date/", json=
        {
            "xx": "yy"

        }
          )
        json_response_dict = response.json()
        request_id = json_response_dict['requestId']
        self.request_list.append(request_id)


    @task
    def store_estimated_delivery_date(self):
        self.client.headers['Content-Type'] = "application/json"
        response = self.client.post("/api/v1/estimated-delivery-date/" + str(self.request_list.pop(0)) + "/assign-order?orderId=1")


class EDDApiUser(HttpLocust):
    task_set = GetDeliveryDateTasks
    min_wait = 1000
    max_wait = 1000
    host = "http://localhost:8080"
4

1 回答 1

19

您可以on_start(self)在传递给task列表之前调用为您准备数据的函数。请参见下面的示例:

from locust import HttpLocust, TaskSet, task

class GetDeliveryDateTasks(TaskSet):

    request_list = []

    def get_estimated_delivery_date(self):
        self.client.headers['Content-Type'] = "application/json"
        response = self.client.post("/api/v1/estimated-delivery-date/", json=
        {
            "xx": "yy"

        }
          )
        json_response_dict = response.json()
        request_id = json_response_dict['requestId']
        self.request_list.append(request_id)

    def on_start(self):
        self.get_estimated_delivery_date()


    @task
    def store_estimated_delivery_date(self):
        self.client.headers['Content-Type'] = "application/json"
        response = self.client.post("/api/v1/estimated-delivery-date/" + str(self.request_list.pop(0)) + "/assign-order?orderId=1")


class EDDApiUser(HttpLocust):
    task_set = GetDeliveryDateTasks
    min_wait = 1000
    max_wait = 1000
    host = "http://localhost:8080"
于 2016-03-15T15:37:07.117 回答