我需要以这种格式打开一个文件
Dat Nguyen 77.7 88.8 99.9 11.1 22.2
Pat Nguyen 2 3 4 5 6
我需要将行的名字分配给结构的成员数组,将行的姓分配给结构的另一个成员,将行的每个编号分配给结构中的分数数组,并且每个新行都转到下一个结构数组的索引,做同样的事情(对不起,如果我措辞不好)。
我的名字和姓氏分配很顺利,但是当将数字分配给结构成员时,它会跳过前三个数字。我究竟做错了什么?
这是我的代码
void fileLoad(Gradebook *students, int &stuCount, int &assignments)
{
ifstream fin;
fin.open("Scores.txt");
if (!fin.is_open())
cout << "Failed to open file.\n";
if (stuCount < 10)
{
int n = 0;
string tempLine;
string line[10];
while (!fin.eof())
{
getline(fin, tempLine);
line[n] = tempLine;
stringstream ss(tempLine);
ss >> students[stuCount].fname >> students[stuCount].lname;
assignments = 0;
for (int i = 0; tempLine[i] != '\0'; i++)
{
ss >> students[stuCount].score[assignments];
if (tempLine[i] == ' ')
assignments++;
}
cout << line[n] << endl;
assignments--;
stuCount++;
n++;
cout << assignments << endl;
}
}
else
cout << "Already max students.\n";
}
这是输出
Dat Nguyen 77.7 88.8 99.9 11.1 22.2
Pat Nguyen 2 3 4 5 6
1. Add a new student to the class
2. Assign grades for a new assignment
3. List one student, displaying all their grades and their course average
4. List all the scores for a chosen assignment
5. Display all grades currently contained in the gradebook
6. Save the gradebook to file
7. Exit the program
Enter choice: 3
Enter a student #: 1
Dat Nguyen
Assignment 1: 11.1
Assignment 2: 22.2
Assignment 3: -9.25596e+61
Assignment 4: -9.25596e+61
Assignment 5: -9.25596e+61
Assignment 6: -9.25596e+61
Average: -5.28912e+61