0

更新 尝试使用以下代码使用 FileTransfer 插件将文件发布到 transloadit

     var uri = encodeURI("https://api2-eu-west-1.transloadit.com/assemblies");
            var options = new FileUploadOptions();
            options.fileKey = "file";
            options.fileName = filepath.substr(filepath.lastIndexOf('/') + 1);

            var params = new Object();
            params.auth =new Object();
            params.auth.key ="***************" ;

            options.params = params; 
            var ft = new FileTransfer();
            ft.upload(filepath, uri, win, fail, options);

我收到错误“no_params_field”、“未提供参数字段”我也尝试将参数作为选项传递

    ft.upload(filepath, uri, win, fail, params);

您能否帮助如何使用 FileTransfer 插件发送 transloadit 参数?

谢谢

4

1 回答 1

2

找到它,它应该被传递为

    var params = {};
            params.params = new Object();
            params.params.auth = {key: "***"};

然后

    ft.upload(filepath, uri, win, fail, {params: params});

谢谢

于 2016-03-18T17:29:20.930 回答