问题:我想根据 json 数据的开始时间和结束时间修剪视频文件。有多个开始和结束时间,需要修剪视频,然后附加最后的部分。
我尝试通过将 unix 时间戳分配给 var 然后使用 datetime 转换为 MM:SS 来使用 MoviePy。
我如何为多个值执行此操作,因为脚本会遍历所有字典并根据数据修剪视频?
MoviePY 是否足以胜任这项工作,还是有其他有效的库/出路?
我尝试了什么:
from moviepy.editor import *
import datetime
start_time = int(datetime.datetime.fromtimestamp(int("1456229360")).strftime('%S'))
end_time = int(datetime.datetime.fromtimestamp(int("1456229334")).strftime('%S'))
print start_time
print end_time
my_clip = VideoFileClip("sample.mp4")
#Trims the video as per the processed timestamps
clip1 = my_clip.subclip(start_time,end_time) #and select the subclip 00:00:00 - 00:00:00
#Append the trimmed parts.
#final_video = concatenate([clip1,clip2,clip3]) #How to do this ?
processed_vid = clip1.write_videofile("final_sample.mp4")
with open('output.json', 'r') as f:
timestamps = json.load(f)
示例 Json 数据:
[
{
"accl": 1.5899999999999999,
"duration": 19,
"end_time": 1434367730,
"start_time": 1434367711
},
{
"accl": 0.7670000000000012,
"duration": 14,
"end_time": 1434368618,
"start_time": 1434368604
},
{
"accl": 0.7129999999999992,
"duration": 11,
"end_time": 1434368692,
"start_time": 1434368681
},
{
"accl": 0.5970000000000013,
"duration": 13,
"end_time": 1434367605,
"start_time": 1434367592
}
]
更新:我尝试做其他事情,我到了那里,但我需要帮助大规模转换这些时间戳,因为moviepy 只接受 HH:MM:SS 而不是 unixtime,并在此基础上创建子剪辑。
from moviepy.editor import *
import datetime
import json
clips_array = []
video= VideoFileClip('sample.mov')
with open('output.json', 'r') as f:
timestamps = json.load(f)
for timestamps in f:
clip = full_vid.subclip(start_time, end_time)
clips_array.append(clip)