我在我的应用程序中使用共享意图,但我无法共享图像和文本,我正在使用我的 json 响应中的图像和文本,但它不起作用。我没有收到任何错误,但是共享方法不管用
JSON 响应: http: //pastie.org/10753346
public void onShareItem(View v) {
// Get access to bitmap image from view
// Get access to the URI for the bitmap
Uri bmpUri = getLocalBitmapUri(descpic);
if (bmpUri != null) {
// Construct a ShareIntent with link to image
Intent shareIntent = new Intent();
shareIntent.setAction(Intent.ACTION_SEND);
shareIntent.putExtra(Intent.EXTRA_STREAM, bmpUri);
shareIntent.putExtra(Intent.EXTRA_TEXT, desc.getText().toString());
shareIntent.setType("image/*");
// Launch sharing dialog for image
startActivity(Intent.createChooser(shareIntent, "Share Image"));
} else {
// ...sharing failed, handle error
}
}
// Returns the URI path to the Bitmap displayed in specified ImageView
public Uri getLocalBitmapUri(ImageView imageView) {
// Extract Bitmap from ImageView drawable
Drawable drawable = imageView.getDrawable();
Bitmap bmp = null;
if (drawable instanceof BitmapDrawable){
bmp = ((BitmapDrawable) imageView.getDrawable()).getBitmap();
} else {
return null;
}
// Store image to default external storage directory
/*Uri bmpUri = null;
try {
File file = new File(Environment.getExternalStoragePublicDirectory(
Environment.DIRECTORY_DOWNLOADS), "share_image_" + System.currentTimeMillis() + ".png");
file.getParentFile().mkdirs();
FileOutputStream out = new FileOutputStream(file);
bmp.compress(Bitmap.CompressFormat.PNG, 90, out);
out.close();
bmpUri = Uri.fromFile(file);
} catch (IOException e) {
e.printStackTrace();
}*/
OutputStream fOut = null;
Uri outputFileUri=null;
try {
File root = new File(Environment.getExternalStorageDirectory()
+ File.separator + "folder_name" + File.separator);
root.mkdirs();
File sdImageMainDirectory = new File(root, "myPicName.jpg");
outputFileUri = Uri.fromFile(sdImageMainDirectory);
fOut = new FileOutputStream(sdImageMainDirectory);
} catch (Exception e) {
Toast.makeText(this, "Error occured. Please try again later.",
Toast.LENGTH_SHORT).show();
}
try {
bmp.compress(Bitmap.CompressFormat.PNG, 100, fOut);
fOut.flush();
fOut.close();
} catch (Exception e) {
}
return outputFileUri;
}