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Following example from python cassandra driver

class Users(Model):
    username = columns.Text(index=True, required=True)
    user_id = columns.UUID(index=True, default=uuid.uuid4)
    email = columns.Text(primary_key=True, required=True)
    passwd = columns.Text()
    salt = columns.Text()

And creating object in following way:

u = Users()
u.username = 'admin'
u.email = 'test@test.com'
u.password = u'test'   #This is property with setter
Users.create(**dict(u))

In this case, we get user_id:None instead of user_id:uuid.uuid4 and corresponding error.

How to make default = uuid.uuid4 work with less pain?

UPD I guess, it's caused by overriding to_database method in UUID column. Which conflicts with base to_database method.

UPD2 Looks like bad case. Error happens on step **dict(u)

Solution:

d = dict(u) 
del d['column_with_default_value']
Users.create(**d)
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1 回答 1

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你做的工作比你需要做的多得多。给定您的表格,这就是您插入的方式:

Users.create(username="admin", email="test@test.com", passwd="test")

我在这里验证了这一点:

In [16]: Users.create(username="admin", email="test@test.com", passwd="test") Out[16]: Users(username='admin', user_id=UUID('183d542d-c469-448d-9d14-d3614f727cef'), email='test@test.com', passwd='test', salt=None)

于 2016-03-08T19:57:10.227 回答