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我正在为 Swift Sqlite 使用 GRDB 库。

我创建了一个连接类：

导入GRDB

var dbQueue: 数据库队列！

功能设置数据库（）{

var config = Configuration()
config.readonly = true
config.foreignKeysEnabled = true
config.trace = { print($0)}



let databasePath = NSBundle.mainBundle().pathForResource("mydb", ofType: "sqlite")!

dbQueue = try! DatabaseQueue(path: databasePath, configuration:  config)

}

我在方法中调用类：

func trovaCitta(luogoNascita: String)->CittaVO{

    let citta:CittaVO = CittaVO()


    dbQueue.inDatabase { db in

        for row in Row.fetch(db, "SELECT * FROM comune where cod_catastale='" + luogoNascita + "'") {
            citta.codIstat = row.value(named: "cod_istat")
            citta.nome = row.value(named: "nome")

                    citta.codProvincia = row.value(named: "cod_provincia")
                    citta.codValidita = row.value(named: "cod_validita")
                    citta.codCap = row.value(named: "cod_cap")
                    citta.codCatastale = row.value(named: "cod_catastale")
          //  print(citta)
        }

    }

    return citta
}

应用程序返回：致命错误：在展开可选值时意外发现 nil

0x1009f8764 <+36>: 移动 x4, x5 0x1009f8768 <+40>: bl 0x100a3add0 ; Swift 的函数签名特化。(_fatalErrorMessage (Swift.StaticString, Swift.StaticString, Swift.StaticString, Swift.UInt) -> ()).(closure #2)

有人可以给我建议吗？谢谢

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1 回答 1

1

我对 SQLite.swift 框架而不是 GRDB 的运气更好。

于 2016-05-31T20:11:09.407 回答