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这是我的尝试，xsd 和从 xsd.exe 创建的类

运行我的代码时出现错误“XML 文档 (1、2) 中存在错误”。内部异常 {" 不是预期的。"}

任何帮助将不胜感激。

谢谢！

XML 片段：

 <xml>
  <creditBureau xmlns="http://www.transunion.com/namespace"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <document>response</document>
    <version>2.2</version>
    <transactionControl>
      <userRefNumber>260907</userRefNumber>
      <subscriber>
        <industryCode>P</industryCode>
        <memberCode>04784547</memberCode>
        <inquirySubscriberPrefixCode>1527</inquirySubscriberPrefixCode>
      </subscriber>...

XSD 片段：

<?xml version="1.0" encoding="utf-8"?>
<xs:schema xmlns:tns="http://www.transunion.com/namespace" 
           attributeFormDefault="unqualified" 
           elementFormDefault="qualified" 
           targetNamespace="http://www.transunion.com/namespace" 
           xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="creditBureau">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="document" type="xs:string" />
        <xs:element name="version" type="xs:decimal" />
        <xs:element name="transactionControl">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="userRefNumber" type="xs:unsignedInt" />
              <xs:element name="subscriber">...

类片段：

[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http://www.transunion.com/namespace")]
[System.Xml.Serialization.XmlRootAttribute(Namespace="http://www.transunion.com/namespace", IsNullable=false)]
public partial class creditBureau {
    private string documentField;
    private decimal versionField;
    private creditBureauTransactionControl transactionControlField;
    private creditBureauProduct productField;

    public string document {
        get {
            return this.documentField;
        }
        set {
            this.documentField = value;
        }
    }

    public decimal version {
        get {
            return this.versionField;
        }
        set {
            this.versionField = value;
        }
    }

    public creditBureauTransactionControl transactionControl {
        get {
            return this.transactionControlField;
        }
        set {
            this.transactionControlField = value;
        }
    }

    public creditBureauProduct product {
        get {
            return this.productField;
        }
        set {
            this.productField = value;
        }
    }
}

代码片段：

    FileStream fs = new FileStream("XMLFile1.xml", FileMode.Open);
    XmlSerializer x = new XmlSerializer(typeof(creditBureau));
    creditBureau c = (creditBureau)x.Deserialize(fs);
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1 回答 1

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假设您发布的 XML 正是您收到的内容，则会发生错误，因为 XML 文档不正确：

<xml>

不是有效的 XML 声明标记，它应该是这样的：

<?xml version="1.0" encoding="utf-8"?>
于 2010-08-25T15:43:50.010 回答