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我正在使用 Ubuntu 14.04，并且我正在 c 中设置一个虚拟键盘，这需要 uinput 才能工作。

我的程序应该将键“a”发送到终端，就像我按下键盘上的“a”键一样。

这是我的源代码：

int main()
{
int uinp_fd;
int i;

/********** Open uinput file section. **********************/

uinp_fd = open("/dev/uinput", O_WRONLY|O_NDELAY);

if(uinp_fd < 0)
{

    printf("Unable to open /dev/uinput\n");
    return -1;
}

else printf("Can open /dev/uinput\n");

/********* Setup input device structure section: ***********/

memset(&uinp,0,sizeof(uinp));

snprintf(uinp.name, UINPUT_MAX_NAME_SIZE, "The C Keyboard");
uinp.id.bustype = BUS_USB;  
uinp.id.version = 1;
uinp.id.vendor = 0x1234;
uinp.id.product = 0xfedc;

write(uinp_fd, &uinp, sizeof(uinp));


/****** Setup the uinput keyboard device section: **********/

ioctl(uinp_fd, UI_SET_EVBIT, EV_KEY);
ioctl(uinp_fd, UI_SET_EVBIT, EV_SYN);
ioctl(uinp_fd, UI_SET_EVBIT, EV_REP);

ioctl(uinp_fd, UI_SET_KEYBIT, KEY_A);

if (ioctl(uinp_fd, UI_DEV_CREATE, NULL) < 0)
{
    printf("Unable to create UINPUT device.\n");
    return -1;
}

/*********** Send keypress events to kernel: ***************/

memset(&event, 0, sizeof(event));
gettimeofday(&event.time, NULL);

event.type = EV_KEY;
event.code = KEY_A;
event.value = 1;
write(uinp_fd, &event, sizeof(event));



event.type = EV_SYN;
event.code = SYN_REPORT;
event.value = 0;
write(uinp_fd, &event, sizeof(event));

/************** Release keypress event: *******************/

memset(&event, 0, sizeof(event));
gettimeofday(&event.time, NULL);

event.type = EV_KEY;
event.code = KEY_A;
event.value = 0;
write(uinp_fd, &event, sizeof(event));

event.type = EV_SYN;
event.code = SYN_REPORT;
event.value = 0;
write(uinp_fd, &event, sizeof(event));

/*** Destroy keyboard device and close the Uinput device: **/

ioctl(uinp_fd, UI_DEV_DESTROY);
close(uinp_fd);

return 0;

}

然而，我的程序什么也没做。它只是打印出来：

Can open /dev/uinput

就是这样……

我究竟做错了什么？感谢您的帮助！

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