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我的性能测试流程需要 JAMon monitor 来完成这些步骤:

  1. 创建,
  2. 连载的
  3. 反序列化
  4. 要停止的反序列化副本

但是下面的场景不起作用(第 4 步没有效果)。

你能给我一个解决方法吗?

用代码证明

public class Main {

    protected static void monitorSomething() throws InterruptedException, IOException, ClassNotFoundException{
        Monitor outerMonitor = MonitorFactory.start("outerMonitor");
        for (int i=1; i<=10; i++) {
            Monitor inner = MonitorFactory.start("myInnerMonitor");
            Monitor serializedMonitorSource = MonitorFactory.start("serializedMonitor");
            Thread.sleep(100+i);
            byte[] serialized = serialize( serializedMonitorSource );
            Monitor serializedMonitorDestination = (Monitor)deserialize( serialized );
            serializedMonitorDestination.stop();
            inner.stop();
        }
        outerMonitor.stop();
        MonitorFactory.start("mySecondMonitor")
                      .stop();

    }

    protected static void printPerformanceMeasurements(){
        for( Object monitor: MonitorFactory.getMap().values() ){
            System.out.println( monitor );  
        }

    }

    public static void main(String[] args) throws InterruptedException, IOException, ClassNotFoundException {
        monitorSomething();
        printPerformanceMeasurements();
    }

    private static byte[] serialize(Serializable serializable)  throws IOException {
        try (ByteArrayOutputStream bos = new ByteArrayOutputStream();
             ObjectOutput out = new ObjectOutputStream(bos)) {
            out.writeObject(serializable);
            byte[] messageBytes = bos.toByteArray();
            return messageBytes;
        }

    }

    private static Object deserialize(byte[] bytes) throws IOException, ClassNotFoundException{
        try (ByteArrayInputStream bis = new ByteArrayInputStream(bytes);
             ObjectInput in = new ObjectInputStream(bis)) {
            return in.readObject();
        }         
    }
}

输出

JAMon Label=myInnerMonitor, Units=ms.: (LastValue=114.0, Hits=10.0, Avg=114.2, Total=1142.0, Min=105.0, Max=136.0, Active=0.0, Avg Active=1.0, Max Active=1.0, First Access=Thu Feb 25 22:01:38 EET 2016, Last Access=Thu Feb 25 22:01:39 EET 2016)
JAMon Label=outerMonitor, Units=ms.: (LastValue=1143.0, Hits=1.0, Avg=1143.0, Total=1143.0, Min=1143.0, Max=1143.0, Active=0.0, Avg Active=1.0, Max Active=1.0, First Access=Thu Feb 25 22:01:39 EET 2016, Last Access=Thu Feb 25 22:01:39 EET 2016)
JAMon Label=mySecondMonitor, Units=ms.: (LastValue=0.0, Hits=1.0, Avg=0.0, Total=0.0, Min=0.0, Max=0.0, Active=0.0, Avg Active=1.0, Max Active=1.0, First Access=Thu Feb 25 22:01:39 EET 2016, Last Access=Thu Feb 25 22:01:39 EET 2016)
JAMon Label=serializedMonitor, Units=ms.: (LastValue=0.0, Hits=0.0, Avg=0.0, Total=0.0, Min=1.7976931348623157E308, Max=-1.7976931348623157E308, Active=10.0, Avg Active=0.0, Max Active=0.0, First Access=Thu Jan 01 02:00:00 EET 1970, Last Access=Thu Jan 01 02:00:00 EET 1970)
JAMon Label=com.jamonapi.Exceptions, Units=Exception: (LastValue=0.0, Hits=0.0, Avg=0.0, Total=0.0, Min=1.7976931348623157E308, Max=-1.7976931348623157E308, Active=0.0, Avg Active=0.0, Max Active=0.0, First Access=Thu Jan 01 02:00:00 EET 1970, Last Access=Thu Jan 01 02:00:00 EET 1970)

请注意,没有测量 serializedMonitor (active=10)

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1 回答 1

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一种解决方法是不序列化整个 Monitor 对象,而仅序列化开始时刻。在测量点,您可以反序列化那个时刻并计算从现在开始的时间差。然后将计算的值添加到 MonitorFactory 统计池。

您可以获得时间执行统计信息(最小值、最大值、平均值)。缺点是您会丢失活动执行的统计信息。

示例代码:

//            Monitor serializedMonitorSource = MonitorFactory.start("serializedMonitor");
        Date measuringStartOriginal = new Date();
        byte[] serialized = serialize( measuringStartOriginal );
        Thread.sleep(100+i);
//            Monitor serializedMonitorDestination = (Monitor)deserialize( serialized );
        Date measuringStartDeserialized = (Date)deserialize( serialized );
//            serializedMonitorDestination.stop();
        Date measuringEnd = (new Date());
        long timeDifference =  measuringEnd.getTime() - measuringStartDeserialized.getTime();
        MonitorFactory.add( "timeDifference", "ms", timeDifference );

结果:

JAMon Label=timeDifference, Units=ms: (LastValue=110.0, Hits=10.0, Avg=106.3, Total=1063.0, Min=102.0, Max=110.0, Active=0.0, Avg Active=0.0, Max Active=0.0, First Access=Mon Feb 29 10:43:57 EET 2016, Last Access=Mon Feb 29 10:43:58 EET 2016)
于 2016-02-29T08:45:20.357 回答