4

我想将此 java 代码翻译成 Frege Haskell：

    PApplet pApplet = new PApplet();
    System.out.print(pApplet.toString());
    PApplet.runSketch(new String[]{"test"}, pApplet);

到目前为止我做了：

data PApplet = mutable native processing.core.PApplet
  where
    native new :: () -> IO PApplet
    native toString :: PApplet -> IO String

native runSketch processing.core.PApplet.runSketch
  :: ArrayOf RealWorld String -> PApplet -> IO ()

main _ = do p <- PApplet.new
            pStr <- p.toString
            putStrLn pStr
            args = JArray.fromList ["test"]
            runSketch args p

部分main编译但后来我得到了这些错误：

E Process.fr:14: type error in expression fromList ("test":[])
    type is : STMutable t1 (JArray String)
    expected: ArrayOf RealWorld String
E Process.fr:15: type error in expression p
    type is : IO PApplet
    expected: PApplet
E Process.fr:12: type error in expression >>= p.toString (λpStr -> >> (putStrLn pStr) (runSketch (fromList ("test":[])) p))
    type is : IO ()
    expected: ()→t1
E Process.fr:11: type error in expression λp -> >>= p.toString (λpStr -> >> (putStrLn pStr) (runSketch (fromList ("test":[])) p))
    type is : IO ()
    expected: ()→t1
E Process.fr:11: type error in expression >>= new (λp -> >>= p.toString (λpStr -> >> (putStrLn pStr) (runSketch (fromList ("test":[])) p)))
    type is : ()→t1
    expected: IO ()
E Process.fr:11: type error in expression λ_ -> >>= new (λp -> >>= p.toString (λpStr -> >> (putStrLn pStr) (runSketch (fromList ("test":[])) p)))
    type is : ()→t1
    expected: IO ()
E Process.fr:12: can't find a type for  p.toString `toString`
    is neither an overloaded function nor a member of  IO PApplet

我正在努力满足编译器标准，但没有成功。在无数次随机组合之后，上面的这个片段对我来说似乎是最合理的。我需要do块中的类型提示吗？我不明白为什么要p <- PApplet.new评估成IO PApplet？以及如何JArray.fromList退货ArrayOf RealWorld String？Frege 很棒，但互操作性非常令人生畏。是否有可能在 Frege github 上有更多关于它的示例？

4

1 回答 1

5

你有

ST s X

你想要

X

而你在IO，这不过是ST RealWorld

因此，最自然的解决方案是在行中=替换<-

args = JArray.fromList ["test"]

你准备好了！

当然，由于类型别名，整个故事有点困难：

type ArrayOf a x = Mutable a (JArray x)
type STMutable s a = ST s (Mutable s a)

是否选择了去锯齿器进行翻译

ST s (Mutable s (JArray String))

回到

ST s (ArrayOf s String)

你可能已经看到了。

于 2016-02-23T16:51:11.213 回答