6

我使用 Syncano 作为 baas，我试图调用外部 API 来接收 JSON 数组。这个 JSON 需要被解析，然后存储在 syncano 中。在此之前，我需要从数据库接收引用对象以将其链接到新的团队对象。

我成功收到了团队（json）数组和参考对象。但我无法存储新数据，因为只有 12-14 个团队（必须是 18 个）被保存。

我用承诺尝试了这个&那个，但没有成功。任何人都可以很好地建议如何重写代码来存储所有数据？谢谢 - 这是我迄今为止所拥有的......

//TODO: get from ARGS when executing this codebox
var teamKey = 394;
var requestURL = 'http://api.football-data.org/v1/soccerseasons/' + teamKey + "/teams";

var request = require("request");
var Syncano = require('syncano');
var Promise = require('bluebird');
var account = new Syncano({
  accountKey: "abc"
});
var promises = [];

//from: http://docs.syncano.io/v1.0/docs/data-objects-filtering
//"_eq" means equals to
var filter = {
  "query": {
    "apikey": {
      "_eq": apiKey
    }
  }
};

request({
  headers: {
    'X-Auth-Token': 'abc'
  },
  url: requestURL,
  'Content-Type': 'application/json;charset=utf-8;',
  method: 'GET',
}, function(error, response, body) {
  if (error) {
    console.log(error);
  } else {
    var json = JSON.parse(body);
    var teamArray = json.teams;
    var newObject;

    account.instance('instance').class('competition').dataobject().list(filter)
    .then(function(compRes) {

        var competitionID = compRes.objects[0].id;
        for (var i = 0; i < teamArray.length; i++) {
          newObject = {
            "name": teamArray[i].name,
            "nameshort": teamArray[i].code,
            "logo": teamArray[i].crestUrl,
            "competition": competitionID
          };

          (account.instance('instance').class('teams').dataobject().add(newObject).then(function(res) {
              console.log(res);
            }).catch(function(err) {
              console.log("Error eq: " + err);
            })
          );
        }
      }).catch(function(err) {
        console.log(err);
      });
  }
});
4

1 回答 1

4

问题可能是您在进行所有保存调用之前完成了请求过程，您可以尝试 Promise.all()：

    account.instance('instance').class('competition').dataobject().list(filter)
    .then(function(compRes) {

        var competitionID = compRes.objects[0].id, promises=[];
        for (var i = 0; i < teamArray.length; i++) {
          newObject = {
            "name": teamArray[i].name,
            "nameshort": teamArray[i].code,
            "logo": teamArray[i].crestUrl,
            "competition": competitionID
          };
          promises.push(account.instance('instance').class('teams').dataobject().add(newObject).then(function(res) {
              console.log(res);
            }).catch(function(err) {
              console.log("Error eq: " + err);
            })
          );
        }
        return Promise.all(promises);
      }).catch(function(err) {
        console.log(err);
      });

如果一次有太多的并行调用是问题，那么一个接一个地调用：

    account.instance('instance').class('competition').dataobject().list(filter)
    .then(function(compRes) {

        var competitionID = compRes.objects[0].id, promise = Promise.resolve();
        function chainToPromise(promise, teamObj, waitTime){
          waitTime = waitTime || 500;
          return promise.then(function(){
            return new Promise(function(resolve, reject){
              setTimeout(resolve, waitTime);
            });
          }).then(function(){
            return account.instance('instance').class('teams').dataobject().add(teamObj);
          }).then(function(res) {
            console.log(res);
          }).catch(function(err) {
            console.log("Error eq: " + err);
          });
        }
        for (var i = 0; i < teamArray.length; i++) {
          newObject = {
            "name": teamArray[i].name,
            "nameshort": teamArray[i].code,
            "logo": teamArray[i].crestUrl,
            "competition": competitionID
          };
           promise = chainToPromise(promise, newObject);
        }
        return promise;
      }).catch(function(err) {
        console.log(err);
      });
于 2016-02-23T01:18:26.437 回答