18

问题:如何向 OkHTTP 添加授权代理。

我知道 OkHTTP 的构建器确实支持代理,尽管我很难设置一个。

/**
 * Given a Url and a base64 encoded password return the contents of a website.
 * @param urlString
 * @param password
 * @return JSON
 */
public String getURLJson(String urlString, String password) {       
        OkHttpClient client = new OkHttpClient.Builder()
                .connectTimeout(60, TimeUnit.SECONDS)
                .writeTimeout(60, TimeUnit.SECONDS)
                .readTimeout(60, TimeUnit.SECONDS)
                .build();

        Request request = new Request.Builder()
          .url(urlString)
          .get()
          .addHeader("authorization", "Basic " + password)
          .addHeader("cache-control", "no-cache")
          .build();

        Response response = null;
        try {
            response = client.newCall(request).execute();
            String string = response.body().string();
            response.body().close();
            return string;
        } catch (IOException e) {
            System.err.println("Failed scraping");
            e.printStackTrace();
        }
        return "failed";
    }

我有 IP / 端口 / 用户名 / 密码。

虽然我不知道如何将它们变成Proxy proxy可以在 client.SetProxy() 中使用的。

它似乎过于复杂,我似乎无法弄清楚。任何帮助,将不胜感激。

4

1 回答 1

45

尝试这个:

int proxyPort = 8080;
String proxyHost = "proxyHost";
final String username = "username";
final String password = "password";

Authenticator proxyAuthenticator = new Authenticator() {
  @Override public Request authenticate(Route route, Response response) throws IOException {
       String credential = Credentials.basic(username, password);
       return response.request().newBuilder()
           .header("Proxy-Authorization", credential)
           .build();
  }
};

OkHttpClient client = new OkHttpClient.Builder()
    .connectTimeout(60, TimeUnit.SECONDS)
    .writeTimeout(60, TimeUnit.SECONDS)
    .readTimeout(60, TimeUnit.SECONDS)
    .proxy(new Proxy(Proxy.Type.HTTP, new InetSocketAddress(proxyHost, proxyPort)))
    .proxyAuthenticator(proxyAuthenticator)
    .build();
于 2016-02-23T02:55:29.283 回答